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baherus [9]
3 years ago
11

If two rays are opposite rays, then they have a common endpoint.​

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0

The statement is true.

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Convert the following equation into<br> slope-intercept form.<br> x + y = -1
madam [21]

Answer:

y=-x-1

Step-by-step explanation:

7 0
3 years ago
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There are 360 mins for a monthly cell phone minutes for 4 people in the family, can each person get the same number of minutes o
telo118 [61]

yes, 360/4 = 90 minutes

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3 years ago
"Trigonometric Models" (50 POINTS)<br> Is my graph right?
ch4aika [34]

Answer:

Yes, this graph is absolutely right for the function y = 2\sin(2x)-3.

Step-by-step explanation:

firstly we will calculate amplitude, period, phase shift, and vertical shift.

Use the standard form a\sin(bx-c)+d to calculate the values of amplitude, period, phase shift, vertical shift.

here a = 2

     b = 2

     c = 0

    d = -3

Amplitude = |a|  = 2

period = \frac{2\pi}{|b|}

           = \frac{2\pi}{2} = \pi

phase shift = \frac{c}{b} = 0

and vertical shift = d = -3

so, by using this information, if we plot the graph then the graph obtained will be same as the given graph.

6 0
3 years ago
QUESTION 16<br> What is the absolute value of -72?
11Alexandr11 [23.1K]

The absolute value of -72 is 72.

Absolute value is essentially just making the number given positive.

If the given number is already positive then the absolute value is the same as the original number

Hope this helped!

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3 years ago
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Derive the equation of the parabola with a focus at (0, −4) and a directrix of y = 4.
CaHeK987 [17]

<u>Answer:</u>

y=-\frac{1}{16} x^2

<u>Step-by-step explanation:</u>

Equation of parabola with focus at (0,-4) and directrix is y=4.

We know that parabola is the locus of all the points such that the distance from fixed point on the parabola to fixed line directrix is the same.

The parabola is opening downwards.

Let any point on parabola is (x,y).

Distance from focus(0,-4) to (x,y) = \sqrt{(x-0)^2+(y-(-4))^2}=|y-4|

\sqrt{(x-0)^2+(y-+4)^2}=|y-4|

(x-0)^2+(y+4)^2=(y-4)^2

(x)^2+(y+4)^2=(y-4)^2

x^2+(y^2+4y+4y+16)=y^2-4y-4y+16

x^2+y^2+8y+16=y^2-8y+16

x^2+16y^2=0

16y=-x^2

y=-\frac{1}{16} x^2

6 0
2 years ago
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