X^2-12x+7=0 move constant to other side
x^2-12x=-7 add the square of half the linear coefficient to both sides...(12/2)^2=36
x^2-12x+36=29 now the left side is a perfect square...
(x-6)^2=29 so if
f(x)=(x-a)^2+b then
f(x)=(x-6)^2-29
So a=6
Answer: 8:15 P.M.
Step-by-step explanation: 3:35 plus a total of 4 hours and 40 minutes
3:35 --- 7:35 ( +4 hours )
7:35 --- 8:15 ( +40 minutes )
