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eduard
3 years ago
5

Alma and Blanca are playing a game where they roll a pair of fair six-sided dice and try to predict the outcomes. Blanca thinks

that the probability of rolling a one and a five is greater than the probability of rolling a one or a five. Alma disagrees. She thinks that the probability of rolling a one or a five is greater.
Based on the sample space of possible outcomes listed below, who is correct, Alma or Blanca?
Mathematics
1 answer:
bulgar [2K]3 years ago
3 0

Answer:

Alma is correct.

Step-by-step explanation:

It is a greater change to roll a 1 or a 5 then both. The chances of rolling both can be a bit high but it is also an easier chance that you will roll one of the other.

If you have 2 dice. To roll a 1 and a 5 you only get one change. But to roll one or the other you have 2 different chances. Therefore if you were to roll both dice you have a higher chance to roll a 1 or a 5 with having two dice.

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Is (2, 2) a solution of y &lt; 4x - 6?<br> Choose 1 answer<br> yes or no
zalisa [80]

No, (2,2) is not solution of y < 4x - 6

Step-by-step explanation:

To solve above linear problem, we use standard method of  Back- Substitution.

First of all, A point (2,2) only becomes solution of equation, if it satisfies equation y < 4x - 6.

Here, the  y < 4x - 6  seems to be like a linear equation.

In this Equation, using  Back- Substitution method,

Point (2,2) : first digit 2 corresponds to x- coordinate and second digit 2 corresponds to y-coordinate.

           y < 4x - 6.....(1)     \\\         x= 2        .....(2)       \\\       y= 2        .....(3)

By putting value of x and y in equation (1),

Equation becomes,

        2 <  4 \times 2  - 6

       2 < 8       -  6

       2 <  2      .... not true mathematically.

Finally, the result came is not true. Therefore, (2,2) is not solution for equation

y < 4x - 6          

4 0
3 years ago
Wha are the equations. of the asymptotes of the graph of the function f(x)=3x^2-2x-1/x^2+3x+10
Leviafan [203]
The asymptote is the line the graph comes close to but never touches, so if you graph it out you should be able to see it! Sorry I couldn't help any more but good luck

3 0
3 years ago
5(6-i)+(6-i)(3-i). show work.
Bumek [7]

47 -14i

You can work this out in the straight-forward way, or you can recognize that (6-i) is a common factor. In the latter case, you have ...

... = (6-i)(5 + 3-i)

... = (6 -i)(8 -i)

This product of binomials is found in the usual way. Each term of one factor is multiplied by each term of the other factor and the results summed. Of course, i = √-1, so i² = -1.

... = 6·8 -6i -8i +i²

... = 48 -14i -1

... =

_____

A suitable graphing calculator will work these complex number problems easily.

4 0
3 years ago
Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.
alina1380 [7]

Answer:

The answer is x=a^{-1}cb^{-1}.

Step-by-step explanation:

First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element g\in G there exist another element, denoted by g^{-1} such that gg^{-1}=e, where e stands for the identity element of G.

So, given the equality axb=c we make a left multiplication by a^{-1} and we obtain:

a^{-1}axb =a^{-1}c.

But, a^{-1}axb = exb = xb. Hence, xb = a^{-1}c.

Now, in the equality xb = a^{-1}c we make a right multiplication by b^{-1}, and we obtain

xbb^{-1} = a^{-1}cb^{-1}.

Recall that bb^{-1}=e and xe=x. Therefore,

x=a^{-1}cb^{-1}.

6 0
3 years ago
Find the value of each power?
sweet [91]
1=-8          l
4=100       l
7=?           l
llllllllllllllllllllll
5 0
3 years ago
Read 2 more answers
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