Let's begin by listing out the information given to us:
8 am
airplane #1: x = 80870 ft, v = -450 ft/ min
airplane #2: x = 5000 ft, v = 900ft/min
1.
We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:
2.
We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:
3.
The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:
Answer:
5 2/3 I think
Step-by-step explanation:
divide 68 by 12
Answer:
f(3) = 68
Step-by-step explanation:
→ f(1) = 2 ⇒ f(2) = f²(2 − 1) + 4
= f²(1) + 4
= 2² + 4
= 8
………………………………………………
→ f(2) = 8 ⇒ f(3) = f²(3 − 1) + 4
= f²(2) + 4
= 8² + 4
= 64 + 4
= 68
$3,500 budget minus $50 clean up fee equals $3,450.
3500 - 50 = 3450
$3,450 divided by $31 per person equals 111.29
3450 / 31 = 111.29
111 people multiplied by $31 equals $3,441 plus $50 clean up fee equals $3,491
111 x 31 = 3441
3441 + 50 = 3491
They can invite 111 people and will have $9 to spare
