Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the A
C = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
the first answer is correct
Simplifies to y=2x-12. slope intercept form is y=MX+b where m is slope and b is intercept do slope 4 and y intercept is -12
The volume of one pan is 192 units cubed. The volume of the three pans is 576 units cubed.
Answer:
y + 13 = 5(x + 2)
Step-by-step explanation:
<h3>Point - slope form of equation: </h3>

Slope intercept of the line : y =5x - 3
Comparing with y = mx +b , m =slope = 5
m = 5 and Point (-2 ,-13)
y - [-13] = 5(x - [-2])
y + 13 = 5(x + 2)