PLEASE HELP ILL MARK AS BRAIN LEIST!

Which of the following shapes has the greatest number of lines of symmetry

jeyben [28]

Circle has the greatest number of lines of symmetry

6 0

3 years ago

Astronauts on the International Space Station commonly face a health issue that some people on Earth experience as well. Researc

Ludmilka [50]

Answer:

C

Step-by-step explanation:

In space you have to exercise 24/7, because if you don't your bones will decay little by little, the same goes for earth, it is a condition that happens if you don't move or exercise.

If possible; can I get brainliest, I mean if it's correct

4 0

2 years ago

Read 2 more answers

Based on the sample of n = 25 healthy-weight students, can you conclude that healthy-weight students eat significantly fewer fat

Elis [28]

Answer:

z = -1.645

Step-by-step explanation:

b) n =25, M = 4.01 , \mu = 4.22 , \sigma = 0.60 , \alpha= 0.05

The hypothesis are given by,

H0 : \mu\geq 4.22 v/s H1 : \mu < 4.22

The test statistic is given by,

Check attachment for the formula that should br here.

z = \frac{4.01- 4.22 }{0.60 /\sqrt{25}}

= -1.75

The critical value of z = -1.645

The calculated value z > The critical value of z

Hence we reject null hypothesis.

The healthy-weight students eat significantly fewer fatty, sugary snacks than the overall population.

8 0

3 years ago

Read 2 more answers

A plane flies 1400 kilometres in 2 hours 30 minutes

Sloan [31]

560 kilometers flied in each hour

8 0

3 years ago

⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden

fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = $\frac{354}{1219}$

n = sample of US adults = 1291

p = population proportion of adults

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

significance level are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $\frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ , $\frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ ]

= [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0

3 years ago