The perimeter and area of the square are 16√5 mm and 80 mm²
<h3 /><h3>How to find perimeter and area of a square?</h3>
Perimeter of a square = 4L
where
Therefore,
Perimeter of a square = 4 × 4√5
Perimeter of a square = 16√5 mm
Area of a square = l²
Area of a square = (4√5)²
Area of a square = 16 × 5
Area of a square = 80 mm²
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Answer:
-4/9
Step-by-step explanation:
Answer:
B. (6√2 + 12) inches
Step-by-step explanation:
The length of the kite edge at upper left is ...
x/sin(45°) = x/(1/√2) = x√2
The length of the kite edge at upper right is ...
x/sin(30°) = x/(1/2) = 2x
The perimeter of the kite is double the sum of the lengths of these edges:
P = 2(x√2 +2x) = 2x(√2 +2)
For x=3 in, this is ...
P = 2·(3 in)(√2 +2)
P = (6√2 +12) in
_____
The sine of an angle is the ratio of the side opposite to the hypotenuse. Here, the side opposite is x, and the hypotenuse is the kite edge of interest.
x/hypotenuse = sin(angle)
hypotenuse = x/sin(angle) . . . . . solve for hypotenuse
Answer:
Step-by-step explanation rational integer and whole numbers:
