AO

1 answer:

iogann1982 [59]2 years ago

3 0

Answer: Summer Math Packet for Students Entering Algebra 2. 1. Percentages ... E) -15+6 = -9 f). 35:-7 = 5 g. 3[2(6+1)-32). 1+(22-1)+1. 1 = 3 h). 4:3 =

Step-by-step explanation: Good luck!

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Какая фигура имеет ось симметрии и центр симетрий

Zigmanuir [339]

Answer:

Проведите линию через форму, чтобы каждая сторона была зеркальным отражением. Когда фигура складывается пополам по оси симметрии, две половинки совпадают. На этой фотографии белая линия по центру представляет собой вертикальную ось симметрии.

Step-by-step explanation:

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2 years ago

What is the domain of the following parabola?

Alex17521 [72]

I think it should be C but let me know if im wrong plz

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3 years ago

Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$