Answer:
6.2
Step-by-step explanation:
Although there's multiple ways to solve this problem, my method will be to simply find the area for the full triangle (the empty + orange triangles) and subtract the area of the smaller, empty triangle.
Now, you that area for a triangle is 1/2*base*height.
To find the measurements for the full triangle, you must add up the bases for the two smaller triangles:

Height is the same for both triangles so Height total = 4 ft.
Now the total area can be calculated:
Area total= 1/2* base_total * height_total
Area total = 1/2 * 5ft * 4 ft
Area total = 20 / 2 = 10 ft squared
Lastly, subtract the area of the empty triangle from the total triangle to find the orange triangle.
Area Empty Triangle = 1/2 * base_empty * height_empty
Area Empty Triangle = 1/2 * 1.9ft * 4 ft = 7.6 ft / 2 = 3.8 ft squared
Area total - Area empty = 10ft^2 - 3.8ft^2 = 6.2 ft squared
Answer: 31
Step-by-step explanation:
To find the distance, find the difference between the number.
23 - (-8) = 31 So the distance is 31 units.
Note: To go from -8 to 23 you will have to add 31 to -8 and to go from 23 to -8 you will have to subtract 31 so the distance is 31
1. Let a and b be coefficients such that

Combining the fractions on the right gives



so that

2. a. The given ODE is separable as

Using the result of part (1), integrating both sides gives

Given that y = 1 when x = 1, we find

so the particular solution to the ODE is

We can solve this explicitly for y :


![\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|](https://tex.z-dn.net/?f=%5Cln%7Cy%7C%20%3D%20%5Cln%5Cleft%7C%5Csqrt%5B3%5D%7B%5Cdfrac%7B5x%7D%7B2x%2B3%7D%7D%5Cright%7C)
![\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B5x%7D%7B2x%2B3%7D%7D%7D)
2. b. When x = 9, we get
![y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B45%7D%7B21%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cdfrac%7B15%7D7%7D%20%5Capprox%20%5Cboxed%7B1.29%7D)