Based on the information given the gain or loss percent on the whole transaction is 1%.
<h3>Gain or loss percent:
</h3>
First step is to calculate the profit on the whole transaction
Profit=(8%×8,000)-(6%×8,000)
Profit=$640-$480
Profit=$160
Now let calculate the gain or loss percentage on the whole transaction
Gain or loss percentage=160/(8000+8000)×100
Gain or loss percentage=160/16000×100
Gain or loss percentage=1%
Inconclusion the gain or loss percent on the whole transaction is 1%.
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Answer:
39 divided by 3 = 13+3=16 therefore Louis is 16 and sanchez i
Step-by-step explanation:
s going to be 23 years of age. Because 39-16=23
Answer:
78 pounds
Step-by-step explanation:
Let's say Yolanda makes a pounds of Type A coffee and b pounds of Type B coffee. Since the total number of pounds is 130, we can write the equation:
a + b = 130
We know the cost of Type A coffee is $5.20/lb and the cost of Type B coffee is $4.05/lb, so since the total cost is $586.30, we can write:
5.20a + 4.05b = 586.30
We can now solve the system of equations:
a + b = 130
5.20a + 4.05b = 586.30
Manipulate the first equation by subtracting b from both sides:
a + b = 130
a = 130 - b
Substitute 130 - b for a in the second equation:
5.20a + 4.05b = 586.30
5.20 * (130 - b) + 4.05b = 586.30
676 - 5.20b + 4.05b = 586.30
Move the terms with b to one side:
1.15b = 89.70
b = 78
Thus, Yolanda used 78 pounds of Type B coffee.
<em>~ an aesthetics lover</em>
Answer:Factor by grouping.
Tap for more steps...
(
x
−
4
)
(
3
x
+
1
)
x
−
4
Reduce the expression by cancelling the common factors.
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3
x
+
1
Step-by-step explanation:
Multiply the equation:

The solution set is the same, because multiplying both sides of an equation by a non-zero number doesn't change the solution set. In fact, if you rewrite the equation as

Multiplying this by 3 (or whatever number, for all it matters) gives

Now, a product is zero if and only if at least one of the factor is zero. So, either
or 
Since the first is clearly impossible, the second one must be true, which is the original equation.