Answer:
we will know that the allelic frequencies are for R 0.95 and r 0.05
Explanation:
We know that the population is in Hardy-Winberg equilibrium, we deduce the following formula:
p + q = 1
p2 + 2pq + q2 = 1
data
R: red flower allele
r: allele blor blanca
p would be equal to the allelic frequency R
q will be equal to the frequency allelic r
2p = RR
2q = rr
2pq = Rr
If there are 25 white flowers in 1000 plants, their frequency will be:
2pq frequency of the Rr genotype
white flower = 25/10000 = 0.0025 = rr = 2q = 0.0025
we deduce that q is equal to 0.05
we replace the data with the previous formula
p + q = 1
p = 1-0.05
we get as a result
p = 0.95
if p = 0.95 and q = 0.05
we will know that the allelic frequencies are for R 0.95 and r 0.05
Answer:
please give me brainlist and follow
Explanation:
Following fertilization the embryonic stage of development continues until the end of the 10th week (gestational age) (8th week fertilization age). The first two weeks from fertilization is also referred to as the germinal stage or preembryonic stage.
The predators will feed on the prey lowering their birthrates, but while feeding on the prey, the predators' growth rate will lower since there is less prey to feed on.
