To test his hypothesis, the student will have to design an experiment to measure the effects of <u>temperature on cellular growth</u>.
To test the effects of temperature on cellular growth the student will have to create an experiment containing the there kinds of variables:
- Dependent
- Independent
- Control
In this experiment, the control variable will be the kind of cells used, as well as the incubation methods being used. We identify these as the control variable given that they will remain constant.
The independent variable will be the Temperature at which we will place each cell being studied. The dependent variable, on the other hand, is by definition, what we seek to measure. In the case given it would correspond to the amount of cellular growth.
To test his theory of the effects of temperature on cellular growth, a student can design an experiment in which the control variable will be the cells themselves, the independent variable will be the Temperature, and the cellular growth can act as the dependent variable.
To learn more:
brainly.com/question/9199868?referrer=searchResults
Please provide an image. But just for reference, a plant cell's main organelles are the cell wall, cell membrane, large water vacuole, nucleus, mitochondria, cloroplast, lysosme, golgi body, and some other organelles that may also be found in animal cells.
Answer:
The correct answer is option B. maculae/ static equilibrium.
Explanation:
Maculae are mechanoreceptors present inside the saccule and utricle specialized for the static equilibrium detecting. Maculae use hair cells to find out the movements of the otolithic membrane occurs, which is the surrounding membrane of the macula.
The sense of the position of the head to determine the stability and posture is static equilibrium and it is determined by the maculae.
Thus, the correct answer is option- B. maculae/ static equilibrium.
Answer:
I'm pretty sure that its A.
Explanation:
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).
