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Bad White [126]
2 years ago
7

Activity

Mathematics
1 answer:
pashok25 [27]2 years ago
4 0

Answer:

2 8

3 27

4 64

5 125

6 204

7 343

8 512

9 729

10 1000

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11.1.30<br> How many three-digit even numbers are possible if the leftmost digit cannot be zero?
Ann [662]

The total number of 3 digit even numbers is 450

Step-by-step explanation:

Step 1 :

We need to determine the  number of 3 digit numbers which is even and the leftmost digit is not zero .

The  3 digits with left most digit not equal to zero starts from 100 and goes up to 998

If we consider only the even 3 digit numbers in this interval, this would form an arithmetic progression with the first number a = 100 and the common difference d = 2.

Step 2:

The last number l  in this series is 998 .

So we have

a = 100

l = 998

d = 2

The nth term in the arithmetic progression is given by a + (n-1) d

so substituting the above values we get

100 + (n-1) 2 = 998

2n = 900  => n = 450

Step 3 :

Answer :

The total number of 3 digit even numbers is 450

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3 years ago
9 to the second power multiply by 3 to the 6 power =3 to the ? power
GenaCL600 [577]

Answer:

Step-by-step explanation:

a^{m} × a^{n} = a^{m+n}

(a^{m})^{n} = a^{mn}

~~~~~~~~~~~~~

9^{2} × 3^{6} = (3²)² × 3^{6} = 3^{2*2+6} = 3^{10}

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3 years ago
5/2x-3 is this a monomial, binomial, or trinomial
Serga [27]
Its a binomial. There are two terms


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Extended rotation rules
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the ratio of the number of people who own a smartphone to the people who own a flip phone is 4 to 3 if 500 more people own a sma
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