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mash [69]
2 years ago
7

(Trignometry, need help please.) A dog is tethered to a 14 foot leash. She travels around an arc of 49 feet. What is the radian

angle she has rotated through? (Reporting bots.)​
Mathematics
1 answer:
saul85 [17]2 years ago
6 0

Element of Circle

the central angle (α) =  (the length of the arc x 360°)/2πr (r = radius)

\alpha =\dfrac{49\times 360^o}{2\pi\times 14}=200.64^o

convert to rad:

\tt 1^o=\dfrac{\pi}{180^o}rad\\\\200^o=\dfrac{200^o\pi}{180^0}rad=\boxed{\bold{3.48~rad}}

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The school buses at a middle school each hold 38 students. The school has, b, buses.
mel-nik [20]

Answer:

38bs

Step-by-step explanation:

multiply the number of students that each bus can hold by the no of buses 38s×b=38bs

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3 years ago
A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

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