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seropon [69]
3 years ago
14

The proof that AMNS AQNS is shown.

Mathematics
1 answer:
FrozenT [24]3 years ago
3 0

Answer:

The answer is "MS and QS".

Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e   MS=SQ

In ΔMNS and ΔQNS

MN=QN       (∵ MNQ is isosceles triangle)

∠NMS=∠NQS     (∵ MNQ is isosceles triangle)

MS=SQ         (Given)

By SAS rule, ΔMNS ≅ ΔQNS.

Hence, segments MS and SQ are therefore congruent by the definition of bisector.

The correct option is MS and QS

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ASHA 777 [7]

Answer:

the graph is in the attachment.

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Step-by-step explanation:

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by using these sketch the region.

I have uploaded the region bounded in the attachment. You may refer it. The region shaded with grey is the required region.

  • to find centroid:

it can be easily identified that the formed region is a triangle

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( See the graph. the three intersection points of the lines are the three vertices of the triangle)

  • for general FORMULA, let the coordinates of three vertices of a triangle PQR be P(a,b) , Q(c,d) , R(e,f)
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  • therefore , the exact coordinates of the centroid =

(\frac{1+0+1}{3}, \frac{2+0+0}{3}  ) = (\frac{2}{3}, \frac{2}{3} )

this point is marked as G in the graph uploaded.

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Answer:

x = 35

Step-by-step explanation:

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