Answer:
The domain is all real numbers less than or equal to two-third
Step-by-step explanation:
<u><em>The question in English is</em></u>
Determine the domain of the function f :D→R, 
we know that
The radicand of the function must be greater than or equal to zero
so
Solve the inequality for x
subtract 2 both sides
Multiply by -1 both sides
Divide by 3 both sides
The solution is the interval ----> (-∞,2/3]
therefore
The domain is all real numbers less than or equal to two-third
4,927 would be the correct answer you just do it on calculator
Answer:
B
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°, thus
p = 180° - (80 + 20)° = 180° - 100° = 80° and
q = 180° - (45 + 55)° = 180° - 100° = 80°
Thus p = q → B
8. The mean of the grades (74) is substantially below the median (88), so the distribution is not symmetrical. Of course, half the grades are below the median, just as half are above the median. However, the mean being 88-74 = 14 points below the median means that the lower half of the grades will have an average at least twice that much, or 28 points, below the median. The distribution of grades must extend quite a bit further to the left of the median than it does to the right. Hence ...
B. The distribution is skewed left.
9. It seems likely the distribution has a number of low grades pulling the average down. There certainly exists the possibility that at least one of them qualifies as an outlier by being more than 1.5 times the IQR below the first quartile. That rule, however, only applies when the distribution is relatively symmetrical, which this one is not. There does not appear to be any recommended way to describe an outlier when the distribution is skewed and has a long tail.*
TRUE: The distribution likely has an outlier.
_____
* Math instruction these days rarely recognizes such subtleties. Since it is probable that at least one value is well below the bottom quartile, I've shown my guess at the expected answer as TRUE. In a real set of grades, I expect the tail of the distribution to have enough low grades that they cannot be considered to be outliers.
Answer:
3 + 5i.
Step-by-step explanation:
(2−√−4)+(1+√−49)
√−4 = 2i and
√−49 = 7i.
So (2−√−4 + (1+√−49
= ( 2 - 2i) + (1 + 7i)
= 3 + -2i + 7i
= 3 + 5i.
