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2 years ago

Range, mode, MAD, median IQR, mean

Mathematics

2 answers:

Jlenok [28]2 years ago

6 0

Answer:

range=8, mode=1 Median=3 mean=4

Step-by-step explanation:

range= subtract largest from smallest

mode= most frequent

median= middle in an ordered data set

Mean= add them all up and divide by how many you addded up

xeze [42]2 years ago

4 0

Answer:

Range : 8

Mode : 1

MAD : N/A

Median : 3

IQR : N/A

Mean : 4

Step-by-step explanation:

Finding Range:

To find range within a set of numbers, you have to find the smallest number, which in this case is 1. And the biggest number, being 9. Then subtract the biggest number by the smallest.

9 - 1

8 is our range.

Finding Mode:

Finding Mode is finding the most common (or repeated) number within the set.

1 , 1 , 3 , 6 , 9

One appears two times unlike all the other numbers appearing once, therefore having 1 as our mode.

Finding MAD :

I have never heard of this term so I wouldn't want to cheat or give you a wrong answer.

Finding Median :

Median is simply finding the number in the middle of the number set.

1 , 1 , 3 , 6 , 9

3 is in the middle of the set, making 3 our median.

Finding IQR :

Like MAD, I have never heard of this term so I wouldn't want to cheat or give you a wrong answer.

Finding Mean :

Mean is adding all the numbers together, then dividing that final value by the amount of numbers there are.

1 + 1 + 3 + 6 + 9

There are five numbers within the set.

20 / 5

4 is our mean.

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The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$

Therefore, the largest angle of the field is 149⁰.

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ddd [48]

Answer:

17.0625

Step-by-step explanation:

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2 years ago

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Verizon [17]

Answer:

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9966 [12]

Answer:

Without tax the shoes would cost £55.9.

Step-by-step explanation:

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