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Tasya [4]
3 years ago
7

ASAP PLS HELP WILL MARK BRAINLIEST!!

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

The lines intersect at (-2,2).

Step-by-step explanation:

The line has an y intercept of 1 and a slope of -1/2 so after graphing the both of them thats where they intersect.  

You might be interested in
Hich of the following are the coordinates of the vertex of y = x2 − 10x + 2?
ANEK [815]
The vertex is in essence the turning point of the parabola y = x²<span> − 10x + 2

the x coordinate of the turning point = </span>- \frac{b}{2a}
                                                         = - \frac{-(10)}{2(1)}
                                                         =  5

when x = 5, y = (5)² - 10(5) + 2
                      = -23

Thus coordinate or vertex is ( 5, -23)

6 0
3 years ago
Identify the graph of the inequality 2(2x-1)+7&lt;13 or-2x + 5≤-10.
xxMikexx [17]

Answer:

Step-by-step explanation:

2

(

2

x

−

1

)

+

7

<

13

Expand LHS

→

4

x

−

2

+

7

<

13

4

x

+

5

<

13

4

x

<

13

−

5

4

x

<

8

Divide through by

4

→

x

<

2

x

<

2

is represented on the real line by the interval

(

−

∞

,

2

)

This can be represented on the

x

y

−

plane by the area to the left of the vertical line

x

=

2

as graph below.

graph{2(2x-1)+7<13 [-10, 10, -5, 5]}

5 0
2 years ago
Foster is centering a photo that is 7 / 1 2 inches wide on a scrapbook page that is 14 inches wide. How far from each side of th
Snowcat [4.5K]
36 inches long divide by 7 and 12
6 0
3 years ago
Y = −(x + 4)2 − 7 vertex
ICE Princess25 [194]

Answer:

The vertex (h,k) is (-4,-7).

Step-by-step explanation:

I assume you are looking for the vertex y=-4(x+4)^2-7.

The vertex form of a quadratic is y=a(x-h)^2+k where the vertex is (h,k) and a tells us if the parabola is open down (if a<0) or up (if a>0). a also tells us if it is stretched or compressed.

Anyways if you compare y=-4(x+4)^2-7 to y=a(x-h)^2+k , you should see that a=-4,h=-4,k=-7.

So the vertex (h,k) is (-4,-7).

3 0
3 years ago
Read 2 more answers
35 POINTS AVAILABLE
aliina [53]

Answer:

Part 1) The length of each side of square AQUA is 3.54\ cm

Part 2) The area of the shaded region is (486\pi-648)\ units^{2}

Step-by-step explanation:

Part 1)

<em>step 1</em>

Find the radius of the circle S

The area of the circle is equal to

A=\pi r^{2}

we have

A=25\pi\ cm^{2}

substitute in the formula and solve for r

25\pi=\pi r^{2}

simplify

25=r^{2}

r=5\ cm

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

SU=r=5\ cm

Let

x------> the length side of the square

Applying the Pythagoras Theorem

5^{2}=x^{2} +x^{2}

5^{2}=2x^{2}

x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

A=\pi r^{2}    

we have

r=AB=18\ units

substitute in the formula

A=\pi (18)^{2}=324\pi\ units^{2}

step 2

Find the length of each side of square BCDE

we have that

AB=18\ units

The diagonal DB is equal to

DB=(2)18=36\ units

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

36^{2}=x^{2} +x^{2}

1,296=2x^{2}

648=x^{2}

x=\sqrt{648}\ units

step 3

Find the area of the square BCDE

The area of the square is

A=(\sqrt{648})^{2}=648\ units^{2}

step 4

Find the area of the smaller circle

The area of the circle is equal to

A=\pi r^{2}    

we have

r=(\sqrt{648})/2\ units

substitute in the formula

A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}  

step 5

Find the area of the shaded region

324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}

7 0
3 years ago
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