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Bezzdna [24]
2 years ago
6

June and Angad have played 30 tennis matches.

Mathematics
1 answer:
Bad White [126]2 years ago
7 0

Answer:

Step-by-step explanation:

a) P (June) = 7/15

b) P (Angad) = 8/15

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Help asappppp? i’m having trouble on wat the 1/4 point is
blagie [28]

Answer:

  (-14, 5.5)

Step-by-step explanation:

Perhaps the easiest way to find the 1/4 point is to find (x, y), then find the midpoint between that and M.

  (x, y) = 2M -(13, 25) = 2(-5, 12) -(13, 25) = (-23, -1)

Then the 1/4 point is ...

  ((-23, -1) +M)/2 = ((-23, -1) +(-5, 12))/2 = (-28, 11)/2 = (-14, 5.5)

_____

If we call the end points A(x, y) and B(13, 25), then we know ...

  M = (A+B)/2

  A = 2M -B . . . . we'll need this in a bit

and the 1/4 point Q is such that ...

  (Q -A)/(B -A) = 1/4

  4Q -4A = B -A . . . . cross multipliy

  Q = (B +3A)/4 = (B +3(2M -B))/4 = (6M -2B)/4 . . . . solve for Q

  Q = (3M -B)/2 . . . . reduce the fractions

  Q = (3(-5, 12) -(13, 25))/2 = (-28, 11)/2 = (-14, 5.5) . . . as above

6 0
3 years ago
-4x+5y-3-11x-y<br><br> Does -3 have a like term?
-BARSIC- [3]

Answer:

nope ❎ ❎ ❎ ❎ ❎ ❎ ❎ ❎

5 0
3 years ago
Read 2 more answers
Thea has a key on her calculator marked $\textcolor{blue}{\bf\circledast}$. If an integer is displayed, pressing the $\textcolor
worty [1.4K]

Answer:

$9$

Step-by-step explanation:

Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.

To find: number that Thea originally entered

Solution:

The final number is $243$.

As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,

the number before $243$ must be $324$.

As previously the number was squared, so the number before $324$ must be $18$.

As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,

the number before $18$ must be $81$

As previously the number was squared, so the number before $81$ must be $9$.

3 0
3 years ago
In 1981, the Australian humpback whale population was 350 and has increased at a rate of 14% each year since then.)
dimulka [17.4K]

Answer:

In 1981, the Australian humpback whale population was 350

Po = Initial population = 350

rate of increase = 14% annually

P(t) = Po*(1.14)^t

P(t) = 350*(1.14)^t

Where

t = number of years that have passed since 1981

Year 2000

2000 - 1981 = 19 years

P(19) = 350*(1.14)^19

P(19) = 350*12.055

P(19) = 4219.49

P(19) ≈ 4219

Year 2018

2018 - 1981 = 37 years

P(37) = 350*(1.14)^37

P(37) = 350*127.4909

P(37) = 44621.84

P(37) ≈ 44622

There would be about  44622  humpback whales in the year 2018

5 0
4 years ago
What is 13(n + 4 + 7m)​
nikklg [1K]

Answer:

91m+13n+52

Step-by-step explanation:

7 0
3 years ago
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