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quester [9]
3 years ago
7

Jon is making hamburgers for a church lunch. He has 42 2/3 lbs of ground beef. How many 1/3 pound hamburgers can he make using a

ll the ground beef?
(Please show work, thank you!)
Mathematics
2 answers:
mote1985 [20]3 years ago
7 0
He can make 128 burgers
Furkat [3]3 years ago
6 0

Answer:

128 hamburgers.

Step-by-step explanation:

Jon is making hamburgers for a church lunch.

He is using \frac{1}{3} pound of beef in one hamburger.

He has the total amount of beef =  42\frac{2}{3} pounds

                                             = \frac{128}{3}

Since in one hamburger he use beef =  \frac{1}{3} pound

\frac{128}{3} pounds of ground beef is used in = \frac{\frac{128}{3} }{\frac{1}{3} }

= \frac{128}{3} × \frac{3}{1}

= \frac{384}{3}

= 128 hamburgers

Jon can make 128 hamburgers using all the ground beef.

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sertanlavr [38]

Answer:

a) 98.522

b) 0.881

c) The correlation coefficient and co-variance shows that there is positive association between marks and study time. The correlation coefficient suggest that there is strong positive association between marks and study time.

Step-by-step explanation:

a.

As the mentioned in the given instruction the co-variance is first computed in excel by using only add/Sum, subtract, multiply, divide functions.

Marks y Time spent x y-ybar x-xbar (y-ybar)(x-xbar)

77                    40 5.1         1.3 6.63

63                     42 -8.9            3.3 -29.37

79                     37 7.1            -1.7 -12.07

86                     47 14.1            8.3 117.03

51                    25 -20.9  -13.7 286.33

78                     44 6.1            5.3 32.33

83                      41 11.1            2.3 25.53

90                     48 18.1            9.3 168.33

65                     35 -6.9           -3.7 25.53

47                    28 -24.9 -10.7 266.43

Covariance=\frac{sum[(y-ybar)(x-xbar)]}{n-1}

Co-variance=886.7/(10-1)

Co-variance=886.7/9

Co-variance=98.5222

The co-variance computed using excel function COVARIANCE.S(B1:B11,A1:A11) where B1:B11 contains Time x column and A1:A11 contains Marks y column. The resulted co-variance is 98.52222.

b)

The correlation coefficient is computed as

Correlation coefficient=r=\frac{sum[(y-ybar)(x-xbar)]}{\sqrt{sum[(x-xbar)]^2sum[(y-ybar)]^2} }

(y-ybar)^2 (x-xbar)^2

26.01        1.69

79.21       10.89

50.41             2.89

198.81       68.89

436.81       187.69

37.21       28.09

123.21        5.29

327.61        86.49

47.61         13.69

620.01         114.49

sum(y-ybar)^2=1946.9

sum(x-xbar)^2=520.1

Correlation coefficient=r=\frac{886.7}{\sqrt{520.1(1946.9)} }

Correlation coefficient=r=\frac{886.7}{\sqrt{1012582.69} }

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c)

The correlation coefficient and co-variance shows that there is positive association between marks and study time. The correlation coefficient suggest that there is strong positive association between marks and study time. It means that as the study time increases the marks of student also increases and if the study time decreases the marks of student also decreases.

The excel file is attached on which all the related work is done.

Download xlsx
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