Given:
The given quadratic polynomial is :

To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,

Equate the polynomial with 0 to find the zeroes.

Splitting the middle term, we get




The zeroes of the given polynomial are -3 and 4.
The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.
A quadratic polynomial is defined as:




Therefore, the required polynomial is
.
Answer:
The answer is to the question is 13
Option A:
V = 1/3 * b^2 * h
V = 1/3 * 10.5^2 * 6
V = 1/3 * 110.25 * 6
V = 220.5
Option B:
V = 1/3 * b^2 * h
V = 1/3 * 3.6^2 * 8
V = 1/3 * 12.96 * 8
V = 34.56
Option C:
V = 1/3 * b^2 * h
V = 1/3 * 4.2^2 * 12
V = 1/3 * 17.64 * 12
V = 70.56
Option D:
V = 1/3 * b^2 * h
V = 1/3 * 6^2 * 8.4
V = 1/3 * 36 * 8.4
V = 100.8
I guess it's 'None of the Above'
Answer: 13.7777777778
Step-by-step explanation: