PLEASE ANSWER THIS QUESTION I REALLY NEED IT TODAY AND WHOEVER DOES THIS, SHE/HE WILL GET LUCK! PLS ANSWER

Find all the real cube roots of each number.<br> -64

Masteriza [31]

Every number has three cube roots.

The only real cube root of -64 is <em>-4</em> .

The other two cube roots of -64 are a pair of complex conjugates.
I'm too lazy to calculate them right now, and you didn't ask for them
anyway.

3 0

4 years ago

Read 2 more answers

The diameter of the circle is 66 centimeters.what is the approximate area of the circle? Use for 3.14

Dmitry [639]

Answer: 3419.46

Step-by-step explanation: A=3.14xR^2. To get radius, half your diameter to be 33. 3.14x33^2

7 0

3 years ago

Ramona and Beezus love to read books. Ramona reads 16 less than 5 times the number of books Beezus reads. Ramona reads 134 books

Fittoniya [83]

I think the answer is 30, because if 134 +16 is 5 times the number of books Beezus reads, than just divide by 4 for the answer of 30

6 0

3 years ago

Read 2 more answers

9. To order books from an online site, the buyer must open an account. The buyer needs a username and a password.

slega [8]

Answer:

a)

i)208827064576

ii)62990928000

b)

i)28179280429056

ii)15214711438080

c)

i)899194740203776

ii)607681858331520

Step-by-step explanation:

a)

i)The alphabet consists of 26 letters.

For the first letter of the username there are 26 options.

For the second letter of the username there are 26 options.

For the third letter of the username there are 26 options.

For the fourth letter of the username there are 26 options.

For the fifth letter of the username there are 26 options.

For the sixth letter of the username there are 26 options.

For the seventh letter of the username there are 26 options.

For the eighth letter of the username there are 26 options.

To get the number of the possible usernames we multiply the number of options for each letter: 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 =26^8=208827064576

ii) If letter cannot be repeated.

For the first letter of the username there are 26 options.

For the second letter of the username there are only 25 options.

For the third letter of the username there are only 24 options.

For the fourth letter of the username there are only 23 options.

For the fifth letter of the username there are only 22 options.

For the sixth letter of the username there are only 21 options.

For the seventh letter of the username there are only 20 options.

For the eighth letter of the username there are only 19 options.

To get the number of the possible usernames we multiply the number of options for each letter: 26 x 25 x 24 x 23 x 22 x 21 x 20 x 19 =62990928000

b) 26 letters+10digits+12special characters=48 options

i) For the first letter of the password there are 48 options.

For the second letter of the password there are 48 options.

For the third letter of the password there are 48 options.

For the fourth letter of the password there are 48 options.

For the fifth letter of the password there are 48 options.

For the sixth letter of the password there are 48 options.

For the seventh letter of the password there are 48 options.

For the eighth letter of the password there are 48 options.

To get the number of the possible usernames we multiply the number of options for each letter: 48 x 48 x 48 x 48 x 48 x 48 x 48 x 48= 48^8=28179280429056

ii) If letter cannot be repeated.

For the first letter of the password there are 48 options.

For the second letter of the password there are only 47 options.

For the third letter of the password there are only 46 options.

For the fourth letter of the password there are only 45 options.

For the fifth letter of the password there are only 44 options.

For the sixth letter of the password there are only 43 options.

For the seventh letter of the password there are only 42 options.

For the eighth letter of the password there are only 41 options.

To get the number of the possible usernames we multiply the number of options for each letter: 48 x 47 x 46 x 45 x 44 x 43 x 42 x 41 =15214711438080

c) 26 uppercase letters+26 lowercase letters +10digits+12special characters=74 options

i) For the first letter of the password there are 74 options.

For the second letter of the password there are 74 options.

For the third letter of the password there are 74 options.

For the fourth letter of the password there are 74 options.

For the fifth letter of the password there are 74 options.

For the sixth letter of the password there are 74 options.

For the seventh letter of the password there are 74 options.

For the eighth letter of the password there are 74 options.

To get the number of the possible usernames we multiply the number of options for each letter: 74 x 74 x 74 x 74 x 74 x 74 x 74 x 74 =74^8=899194740203776

ii) If letter cannot be repeated.

For the first letter of the password there are 74 options.

For the second letter of the password there are only 73 options.

For the third letter of the password there are only 72 options.

For the fourth letter of the password there are only 71 options.

For the fifth letter of the password there are only 70 options.

For the sixth letter of the password there are only 69 options.

For the seventh letter of the password there are only 68 options.

For the eighth letter of the password there are only 67 options.

To get the number of the possible usernames we multiply the number of options for each letter: 74 x 73 x 72 x 71 x 70 x 69 x 68 x 67 =607681858331520

7 0

3 years ago

I draw five cards from a randomly shuffled deck. What is the probability that those five cards are in either ascending or descen

Viefleur [7K]

Answer: The probability of drawing 5 cards in either ascending or descending order out of the deck of 52 standard playing cards is 0.84%.

Step-by-step explanation: We have the following cards in a deck: 1(ace), 2, 3, 4, 5, 6, 7, 8, 9, 10, 12(Jack), 13(Queen), 14(King) (thirteen different in total). There are 4 copies of each of them yielding 52 cards in total. First to draw all of the cards in the ascending order all of the drawn cards need to be different. Imagine you have 13 piles of 4 identical cards. Let us calculate the number of ways you can select 5 different ones (the order matters). First you select 5 different piles (this secures that each card is different) and this is possible to do in $\frac{13!}{(13-5)!}$ (we use the formula for variations since the order matters). Now, each card in the pile can be selected in $4$ different ways so the total number of sequences with $5$ different cards is $4^5\frac{13!}{(13-5)!}$ . Now we select out of these sequences the clases of those that contain exactly the same cards but in different order. Only 4 of the sequences within the same class will be in ascending order out of 4*5! which is the total number of the sequences within the class! This means that we have to multiply our total number of sequences of 5 different cards by $\frac{4}{4\cdot 5!}=\frac{1}{5!}$ and this yields the final answer of total number of ascending sequences to be

$4^5\frac{13!}{(13-5)!5!}.$

The total number of possible ways to draw 5 out of 52 cards is just

$\frac{52!}{(52-5)!}.$

This yields for the probability

$\frac{4^5\frac{13!}{(13-5)!5!}}{\frac{52!}{(52-5)!}}=0.42\%$

Exactly the same calculation applies for the descending order. So the probabilty of the cards being in either ascending or descending order is just the sum of these two (the events are mutually exclusive, you cannot have both the ascending and descending order at the same time) yielding the final probability of $0.84\%$ .

6 0

3 years ago