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Andru [333]
2 years ago
15

Could someone please help me out with this

Mathematics
1 answer:
Mkey [24]2 years ago
5 0

Answer:

# 2,9 are declareitive .......... .......

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Len [333]
The answer is C. $34.00
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2 years ago
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What is the difference of the rational expressions below? x/x-2 - 3/x
Lera25 [3.4K]

Answer:

x^2-3x+6/x^2-2x

Step-by-step explanation:

5 0
3 years ago
A certain television is advertised as a 50-inch TV (the diagonal length). If the width of
Anvisha [2.4K]

Hello there i hope you are having a great day :) Your question: A certain television is advertised as a 50-inch TV (the diagonal length). If the width of  the TV is 14 inches, how many inches tall is the TV?

So you would need to used the Pythagorean theorem that would be

c^2 = a^2 + b^2

So this would equal letter C as The hypotenuse of the right angle and also letter A and B are the stands on the triangle so C would equal 50 inches and A and B would equal 14 inches.

Then the Hard bit so you would be,

1) a^2 = c^2 - b^2

2) a = √c^2 - b^2

3) a =  50^2 - 14^2

4) a = √ 2,500 - 196

5) a = √2,304

6) A = 26

So the answer would be 26 Hopefully ❤

3 0
3 years ago
10 points!!! please help :(
daser333 [38]
To complete the identity, we need these fundamental identities:

1)\displaystyle{sec(x)=\frac{1}{cos(x)}

2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)

\displaystyle{csc(x)= \frac{1}{sin(x)}


Thus, by identity 1 we have:

\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}

by identity :

\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)

recall the values :

\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\

\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0, 


so: 

cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)


Putting all these together, we have:


\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}

which is equal to csc(\theta), by identity 3


Answer: D
7 0
3 years ago
Your friend made a spare in the fourth did you?
Bas_tet [7]
Yes you or I have ecause thats what friends do.
8 0
3 years ago
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