Can u plz help me look at the photo PLZ NO LINKS

Mathematics

1 answer:

djyliett [7]2 years ago

8 0

Answer:

0.07

Step-by-step explanation:

The hundredths place is the place between the tenths and thousandths place. For example, the digit in the tenths place in 0.073 is 7.

To round to the nearest hundredth, we look to the digit right of the hundredth digit, 7. We notice that the digit in the thousandths place is 3. When rounding, if a number is 4 or less, we change that digit to a 0, along with the digits beyond it. If a number is 5 or more, we bump up the digit to the next number. Since 3 is less than 4, we change 0.073 to 0.07.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

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Answer:

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Step-by-step explanation:

<u>Given</u>

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<u>Solve for h</u>

S = 2πr² + 2πrh
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3 years ago

Which expression is equivalent to 0.7×0.23

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A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t

Katyanochek1 [597]

The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability) is the opposite of (no car probability) In this case, the easier way is
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability)
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2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
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This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

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3 years ago

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Oksanka [162]

The statement is true.

P(A|B) is the probability of occurrence of event A, provided that(given that) event B has already occurred.

This is known as conditional probability. In conditional probability, the event on right side of the vertical bar (which is B in this case) is given to have already occurred (either we assume this, or some evidence is given about this) and we calculate the probability of event on left of the vertical bar (which is A in this case) based on this information. The formula of condition probability is:

$P(A|B)= \frac{P(A*B)}{P(B)}$

P(A*B) indicates the probability of intersection of event A and B.

So the correct answer is TRUE.

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3 years ago