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kvv77 [185]
2 years ago
12

TO

Mathematics
1 answer:
daser333 [38]2 years ago
8 0

Answer:

90% of people marry their 7th-grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently, if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say I love you

Step-by-step explanation:

do it it works

You might be interested in
Candice and christ run a relay race at recess. Candice runs 1/2 of a lap around the track. Chris runs 1/3 of a lap around the tr
eduard

Answer:

Candice ran 1/6 of a lap further than Chris.

Step-by-step explanation:

we know that

To find out how much further Candice runs than Chris, subtract the distance Chris runs from the distance Candice runs

so

\frac{1}{2}-\frac{1}{3}=\frac{3-2}{6}=\frac{1}{6}\ lap

therefore

Candice ran 1/6 of a lap further than Chris.

5 0
3 years ago
Rectangle ABCD was dilated to create rectangle A'B'C'D. Triangle A B C D is dilated to form triangle A prime B prime C prime D.
Julli [10]

Answer:

AB = 6

Step-by-step explanation:

Given

BC = 3.8

A'B' = 15

B'C' = 9.5

Required

Determine the length of AB

Because A'B'C'D is a dilation of ABCD, then the following relationship must exist:

A'B' : AB = B'C' : BC

Substitute values for A'B', B'C' and BC

15 : AB = 9.5 : 3.8

Express the ratio as fractions:

\frac{AB}{15} = \frac{3.8}{9.5}

Multiply through by 14

15 * \frac{AB}{15} = \frac{3.8}{9.5} * 15

AB = \frac{3.8}{9.5} * 15

AB = \frac{3.8* 15}{9.5}

AB = \frac{57}{9.5}

AB = 6

8 0
3 years ago
Read 2 more answers
Please help 15 points and will give brainliest
Andrej [43]

Answer:

Think it is A as 4x20=80.

8 0
3 years ago
Consider the following function.
Kryger [21]

Answer:

See below

Step-by-step explanation:

I assume the function is f(x)=1+\frac{5}{x}-\frac{4}{x^2}

A) The vertical asymptotes are located where the denominator is equal to 0. Therefore, x=0 is the only vertical asymptote.

B) Set the first derivative equal to 0 and solve:

f(x)=1+\frac{5}{x}-\frac{4}{x^2}

f'(x)=-\frac{5}{x^2}+\frac{8}{x^3}

0=-\frac{5}{x^2}+\frac{8}{x^3}

0=-5x+8

5x=8

x=\frac{8}{5}

Now we test where the function is increasing and decreasing on each side. I will use 2 and 1 to test this:

f'(2)=-\frac{5}{2^2}+\frac{8}{2^3}=-\frac{5}{4}+\frac{8}{8}=-\frac{5}{4}+1=-\frac{1}{4}

f'(1)=-\frac{5}{1^2}+\frac{8}{1^3}=-\frac{5}{1}+\frac{8}{1}=-5+8=3

Therefore, the function increases on the interval (0,\frac{8}{5}) and decreases on the interval (-\infty,0),(\frac{8}{5},\infty).

C) Since we determined that the slope is 0 when x=\frac{8}{5} from the first derivative, plugging it into the original function tells us where the extrema are. Therefore, f(\frac{8}{5})=1+\frac{5}{\frac{8}{5}}-\frac{4}{\frac{8}{5}^2 }=\frac{41}{16}, meaning there's an extreme at the point (\frac{8}{5},\frac{41}{16}), but is it a maximum or minimum? To answer that, we will plug in x=\frac{8}{5} into the second derivative which is f''(x)=\frac{10}{x^3}-\frac{24}{x^4}. If f''(x)>0, then it's a minimum. If f''(x), then it's a maximum. If f''(x)=0, the test fails. So, f''(\frac{8}{5})=\frac{10}{\frac{8}{5}^3}-\frac{24}{\frac{8}{5}^4}=-\frac{625}{512}, which means (\frac{8}{5},\frac{41}{16}) is a local maximum.

D) Now set the second derivative equal to 0 and solve:

f''(x)=\frac{10}{x^3}-\frac{24}{x^4}

0=\frac{10}{x^3}-\frac{24}{x^4}

0=10x-24

-10x=-24

x=\frac{24}{10}

x=\frac{12}{5}

We then test where f''(x) is negative or positive by plugging in test values. I will use -1 and 3 to test this:

f''(-1)=\frac{10}{(-1)^3}-\frac{24}{(-1)^4}=-34, so the function is concave down on the interval (-\infty,0)\cup(0,\frac{12}{5})

f''(3)=\frac{10}{3^3}-\frac{24}{3^4}=\frac{2}{27}>0, so the function is concave up on the interval (\frac{12}{5},\infty)

The inflection point is where concavity changes, which can be determined by plugging in x=\frac{12}{5} into the original function, which would be f(\frac{12}{5})=1+\frac{5}{\frac{12}{5}}+\frac{4}{\frac{12}{5}^2 }=\frac{43}{18}, or (\frac{12}{5},\frac{43}{18}).

E) See attached graph

5 0
3 years ago
1. Solve the inequality.
Sauron [17]

Answer:

Your final answer is either

x≥-2   if your initial inequality was

6x+2≤2(5-x)

OR

x≤-2

if your initial inequality was

6x+2≥2(x-2)

Step-by-step explanation:

As shown you have an equality, not an inequality.

-6x+2=2(5-x)          distribute through parenthesis

-6x+2=2(5)+2(-x)

-6x+2=10-2x           add 2x to both sides

2x-6x+2=10-2x+2x

-4x+2=10                subtract 2 from both sides

-4x+2-2=10-2

-4x=8                      divide both sides by -4

-4x/(-4) = 8/(-4)

x = -2

With the ≥ or ≤ sign you would solve the exact same way

except for the point where when dividing both sides by

-4 requires you to reverse the inequality.

Your final answer is either

x≥-2   if your initial inequality was

6x+2≤2(5-x)

OR

x≤-2

if your initial inequality was

6x+2≥2(x-2)

7 0
3 years ago
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