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allsm [11]
4 years ago
7

In converting 9 yards to inches, what unit (omit the number) would you place in the numerator of your ratio? Remember that there

are 36 inches in 1 yard
Mathematics
1 answer:
mamaluj [8]4 years ago
5 0

Answer:

  inches

Step-by-step explanation:

The "to" unit goes in the numerator. (The "from" unit goes in the denominator.) Since we're converting to inches, the numerator of the conversion factor has units of inches.

_____

  9 yd = 9 yd × (36 in)/(1 yd) = 324 in

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What is the solution to this equation? 2ln4+lnx=3ln2+ln(x+1)
Galina-37 [17]

Answer:

x=1

Step-by-step explanation:

Given equation:

2 \ln 4+\ln x=3 \ln 2+\ln(x+1)

\textsf{Apply the power law}: \quad n \ln x = \ln x^n

\implies \ln 4^2+\ln x=\ln 2^3+\ln(x+1)

Simplify:

\implies \ln 16+\ln x=\ln 8+\ln(x+1)

Subtract ln 8 from both sides:

\implies \ln 16+\ln x- \ln 8=\ln(x+1)

Subtract ln x from both sides:

\implies \ln 16-\ln 8=\ln(x+1)-\ln x

\textsf{Apply the quotient law}: \quad \ln x - \ln y = \ln \frac{x}{y}

\implies \ln \left\dfrac{16}{8}\right = \ln \left(\dfrac{x+1}{x}\right)

Simplify:

\implies \ln 2 = \ln \left(\dfrac{x+1}{x}\right)

\textsf{Apply the equality law}: \quad \textsf{if }\: \ln x= \ln y\:\textsf{ then }\:x=y

\implies 2=\dfrac{x+1}{x}

Multiply both sides by x:

\implies 2x=x+1

Subtract x from both sides:

\implies x=1

5 0
2 years ago
Which shows the expression below simplified? 0.000085 - (4.1 × 10-6) A. 8.09 × 10-5 B. 8.09 × 10-6 C. 4.4 × 10-5 D. 4.099915 × 1
rjkz [21]

Answer:

A. 8.09 × 10^-5

Step-by-step explanation:

4.1 x 10^-6 = 0.0000041

0.000085 - 0.0000041 = 0.0000809

0.0000809 = 8.09 x 10^-5

3 0
3 years ago
HELPPPPPPP on this question.! I need to pass.
timurjin [86]

9514 1404 393

Answer:

  12.25 (or -18.75)

Step-by-step explanation:

If you pay attention to the square of a binomial, ...

  (x -a)² = x² -2ax +a²

You see that the constant (a²) is the square of half the x-coefficient. That is, the x-coefficient is -2a, half that is -a, and the square of that is (-a)² = a².

In your equation, the x-coefficient is -7, half that is -3.5, and the square of that is 3.5² = 12.25.

So, you can think of this ambiguous question in a couple of ways.

<u>Concern is only with the x-terms</u>:

  x² -7x +31 = (x² -7x +12.25) +31 = 12.25 . . . . . . add 12.25 to both sides

  (x -3.5)² +31 = 12.25 . . . . write the x-terms as a square

<u>Concern with the equation overall</u>:

You want the end result to have the x-terms in the form of the square ...

  (x -3.5)² = x -7x +12.25

The left side of the equation can be put in that form by adding -18.75 to both sides;

  x² -7x +31 -18.75 = -18.75 . . . . . . add -18.75 to both sides

  x² -7x +12.25 = -18.75 . . . . . . . . . simplify

  (x -3.5)² = -18.75 . . . . . . write the left side as a square

__

The short of it is that we're not sure what the question is asking for exactly. The "help video" would probably clarify the intent. Most likely, you're concerned with adding the square of half the x-coefficient, 12.25.

3 0
3 years ago
Rationalise the denominator <br>​
Margaret [11]

Step-by-step explanation:

1. \frac{2 \sqrt{3} }{ \sqrt{5} }

multiply

\sqrt{5}

do both the numerator and denominater

\frac{2 \sqrt{3} }{ \sqrt{5} }   \times  \frac{ \sqrt{5} }{ \sqrt{5} }  =  \frac{2 \sqrt{15} }{ \sqrt{25} }  =  \frac{2 \sqrt{15} }{5}

8 0
3 years ago
Lusia tiene $500, decide gastar el 15% de esta cantidad en la compra de un postre para despues de la comida
Morgarella [4.7K]

Answer:

Gasto en postre= $75

Step-by-step explanation:

Dada la siguiente información:

Lusia tiene $500, decide gastar el 15% de esta cantidad en la compra de un postre para despues de la comida.

<u>Para calcular la cantidad a gastar en el postre, debemos usar la siguiente formula:</u>

Gasto en postre= presupuesto total*porcentaje para postre

Gasto en postre= 500*0.15

Gasto en postre= $75

6 0
3 years ago
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