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2 years ago

Try again A light bulb consumes 5040 watt-hours in 3 days and 12 hours. How many watt-hours does it consume per day

Mathematics

1 answer:

White raven [17]2 years ago

5 0

Answer:

1680 watt-hours

Step-by-step explanation:

consume per day

#carry on learning

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the side is in the shape of a rectangle with an area of 437 square centimeters the length of the rectangle is 19 centimeters wha

miss Akunina [59]

The area of the rectangle is length times width, that is
A = L*W
The problem requires the width so
W = A/L
Given that A = 437 sq. cm and L = 19 cm, therefore
W = 437/19 = 23 cm

That is the answer.

5 0

4 years ago

How can you break a table into two part

AveGali [126]

With a saw?

explanation:

6 0

3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

Factorise completely:<br> 1. 3xy - x<br>2. 4a² - 9

Amanda [17]

Answer:

x(3y - 1) and (2a - 3)(2a + 3)

Step-by-step explanation:

(1)

3xy - x ← factor out x from each term

= x(3y - 1)

(2)

4a² - 9 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

4a² - 9

= (2a)² - 3²

= (2a - 3)(2a + 3)

6 0

2 years ago

I need help is it A B C or D

Evgesh-ka [11]

Y=12/x
12/2=6
12/4=3
12/8=1.5 or 3/2
12/12=1
Answer is b

4 0

3 years ago