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3 years ago

9

Evaluate 5a+3b and (5+a)(3+b) for a=2 and b=4. How is the order of the steps different for the two expressions?

1 answer:

Lynna [10]3 years ago

7 0

5a+3b
5(2)+3(4)
10+12
22

(5+a)(3+b)
(5+2)(3+4)
(7)(7)
49

The order of the steps differ for the two expressions because for the first expression, you multiply 5a and 3b first. Then, you add them together. However, for the second expression, you add what's inside the parenthesis first then multiply them. So, the order of the steps is the opposite of the other expression.

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What is the rate of change of y=-3x - 2

maksim [4K]

Answer:

-3

Step-by-step explanation:

The rate of change is equal to the slope. In this slope intercept form (y=mx+b) m is the slope. Therefore m=-3 and that is the rate of change.

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3 years ago

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3 years ago

James has 21 cups of flour he will pour the flour equally into 4 container how many cups of flour will be in each container

Degger [83]

Answer:

5 1/4 cups of flour will be in each container

Step-by-step explanation:

21 ÷ 4= 5.25

5.25= 5 1/4

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3 years ago

Which expression is equivalent to...? Assume... screenshots attached, please help!

larisa [96]

Answer:

$\frac{\sqrt[3]{5} }{3x}$

Step-by-step explanation:

Ok, let's do this step by step....

$\sqrt[3]{\frac{10x^{5} }{54x^{8} } }$

Let's first simplify the x's:

$\sqrt[3]{\frac{10}{54x^{3} } }$

Then we breakdown the 54 as 2 * 27 then simplify with the 10 above.

$\sqrt[3]{\frac{10}{2 * 27x^{3} } } = \sqrt[3]{\frac{5}{27x^{3} } }$

Now, we can rewrite this as the following and solve the bottom part:

$\frac{\sqrt[3]{5} }{\sqrt[3]{27x^{3} } } = \frac{\sqrt[3]{5} }{3 \sqrt[3]{x^{3} } } = \frac{\sqrt[3]{5} }{3x}$

The solution is

$\frac{\sqrt[3]{5} }{3x}$

8 0

4 years ago

A goblet contains 2 red marbles, 6 green marbles, and 4 blue marbles.

ira [324]

Answer:

P(first marble will be green and the second will be green as well)= 5/22

Step-by-step explanation:

A goblet contains 2 red marbles, 6 green marbles, and 4 blue marbles.

Total number of marbles= 2+6+4

=12

P(first marble is green)=no. of green marbles/total number of marbles

= 6/12

= 1/2

P(second marble is green and we didn't put the first marble back)

=no. of green marbles left/total marbles left

= 5/11

Hence, P(first marble will be green and the second will be green as well)

= $\dfrac{1}{2}\times \dfrac{5}{11}$

= 5/22

5 0

4 years ago