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garri49 [273]
3 years ago
9

Evaluate 5a+3b and (5+a)(3+b) for a=2 and b=4. How is the order of the steps different for the two expressions?

Mathematics
1 answer:
Lynna [10]3 years ago
7 0
5a+3b
5(2)+3(4)
10+12
22

(5+a)(3+b)
(5+2)(3+4)
(7)(7)
49

The order of the steps differ for the two expressions because for the first expression, you multiply 5a and 3b first. Then, you add them together. However, for the second expression, you add what's inside the parenthesis first then multiply them. So, the order of the steps is the opposite of the other expression. 
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<h2>Explanation:</h2>

in this problem we have the following expression:

1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}

So here:

1 \frac{1}{2} \ and \ 1 \frac{1}{9} \ are \ written \ as \ mixed \ fractions

Let's convert them as improper fractions:

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\frac{3}{2}\times 3 \times \frac{10}{9}=\frac{3\times 3 \times 10}{2\times 9}=\frac{90}{18}=5

<h2>Learn more:</h2>

Simplify: brainly.com/question/10644722

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