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Tasya [4]
2 years ago
14

How many vertices does the pyramid have?

Mathematics
1 answer:
Westkost [7]2 years ago
6 0

Answer:

5 vertices

Step-by-step explanation:

At base = 4 vertices

On top = 1 vertex

Total = 5 vertices

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2b-5/b-2 = 3/b+2<br><br><br><br> SOLVE
Deffense [45]
Cross multiply:-

3(b - 2) = (2b - 5)(b + 2)

3b - 6 = 2b^2 + 4b - 5b - 10

2b^2 - 4b - 4 = 0

b^2 - 2b - 2 = 0

b = 2.73, -0.73  Answer
7 0
3 years ago
Explain how 2 plus 2 Equals 4
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You have 2+2 in each 2 there are 1's so

2=(1+1) 2=(1+1) =4
4=1+1+1+1
2+2=4
think of 2's as 1's when adding did you know 2x2= 4 as well.
3 0
2 years ago
Read 2 more answers
1.What basic trigonometric identity would you use to verify that cot x sin x = cos x? . .
zavuch27 [327]
1 ) cot x * sin x = cos x
(cos x / sin x) * sin x = cos x 
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3 0
3 years ago
A pizza pan is removed at 9:00 PM from an oven whose temperature is fixed at 450°F into a room that is a constant 70°F. After 5​
gladu [14]

Answer:

A) It will get to a temperature of 125°F at 9:19 PM

B) It will get to a temperature of 150°F at 9:16 PM

C) as time passes temperature approaches the initial temperature of 450°F

Step-by-step explanation:

We are given;

Initial temperature; T_i = 450°F

Room temperature; T_r = 70°F

From Newton's law of cooling, temperature after time (t) is given as;

T(t) = T_r + (T_i - T_r)e^(-kt)

Where k is cooling rate and t is time after the initial temperature.

Now, we are told that After 5​ minutes, the temperature is 300°F.

Thus;

300 = 70 + (450 - 70)e^(-5k)

300 - 70 = 380e^(-5k)

230/380 = e^(-5k)

e^(-5k) = 0.6053

-5k = In 0.6053

-5k = -0.502

k = 0.502/5

k = 0.1004 /min

A) Thus, at temperature of 125°F, we can find the time from;

125 = 70 + (450 - 70)e^(-0.1004t)

125 - 70 = 380e^(-0.1004t)

55/380 = e^(-0.1004t)

In (55/380) = -0.1004t

-0.1004t = -1.9328

t = 1.9328/0.1018

t ≈ 19 minutes

Thus, it will get to a temperature of 125°F at 9:19 PM

B) Thus, at temperature of 150°F, we can find the time from;

150 = 70 + (450 - 70)e^(-0.1004t)

150 - 70 = 380e^(-0.1004t)

80/380 = e^(-0.1004t)

In (80/380) = -0.1004t

-0.1004t = -1.5581

t = 1.5581/0.1004

t ≈ 16 minutes.

Thus, it will get to a temperature of 150°F at 9:16 PM

C) As time passes which means as it approaches to infinity, it means that e^(-kt) gets to 1.

Thus,we have;

T(t) = T_r + (T_i - T_r)

T_r will cancel out to give;

T(t) = T_i

Thus, as time passes temperature approaches the initial temperature of 450°F

6 0
3 years ago
What is the cosine of angle a?<br> a. 8/17<br> b. 15/8<br> c. 15/17<br> d. 8/15
jolli1 [7]
Check the picture below.

6 0
3 years ago
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