The axis of symmetry of the quadratic equation y = 2x^2 + 3 is x = 0
<h3>How to determine the axis of symmetry?</h3>
The equation is given as:
y = 2x^2 + 3
Differentiate the above equation with respect to x
y' = 4x + 0
This gives
y' = 4x
Set the equation to 0
4x = 0
Divide both sides by 4
x = 0
Hence, the axis of symmetry is x = 0
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Answer:
The first option: As the x-values go to positive infinity, the function's values go to negative infinity.
Step-by-step explanation:
Let's focus on the right part of the graph. Notice that at x = 1, the line is on the negative y-axis. The same thing happens to when we locate x = 2, it still continues to go down approaching negative infinity.
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