Answer: b is the answer
Step-by-step explanation:
<span>D. Line AE equals about line ED because if you measure line AE it is the same length as line ED</span>
Answer:
The table a not represent a proportional relationship between the two quantities
The table b represent a proportional relationship between the two quantities
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form
or 
<u><em>Verify each table</em></u>
<em>Table a</em>
Let
A ----> the independent variable or input value
B ----> the dependent variable or output value
the value of k will be

For A=35, B=92 ---> 
For A=23, B=80 ---> 
the values of k are different
therefore
There is no proportional relationship between the two quantities
<em>Table b</em>
Let
C ----> the independent variable or input value
D ----> the dependent variable or output value
the value of k will be

For C=20, D=8 ---> 
For C=12.5, D=5 ---> 
the values of k are equal
therefore
There is a proportional relationship between the two quantities
The linear equation is equal to

Answer: 
Step-by-step explanation:
Factor theorem : If x=a is a zero of a polynomial p(x) then (x-a) is a factor of p(x).
Given: Zeroes of polynomial : -4,0, 1, and 4.
Then Factors =
[By factor theorem ]

Multiplying these factors to get polynomial in standard form.

Hence, B is the correct option.