All categories

2 years ago

Which algebraic expression is equivalent to the expression below? 6(4x + 5) + 11

Mathematics

1 answer:

Alina [70]2 years ago

3 0

Answer:

24x + 41

Step-by-step explanation:

Distribute the 6.

6(4x + 5) + 11 = 24x + 30 + 11

Now we just add the 30 and the 11 which are at the back of the expression.

24x + 30 + 11 = 24x + 41

Therefore the answer is 24x + 41. Please mark brainliest if possible and i hope you get a good grade on your homework

You might be interested in

Ross paints a wall in her bedroom she puts green paint on 5/8 of the wall and blue paint on 3/8 of the wall which of the followi

valina [46]

Both of the fractions can be added since they both have 8 as the denominator 3/8+5/8=8/8 which is a whole.

7 0

3 years ago

Help please for my test 3.

satela [25.4K]

Step-by-step explanation:

first do the parenthesis

4x-3(3x+3x)>18

4x-3(6x)>18

4x-18x>18

-14x>18

I'm not sure if this helps but I tried

8 0

2 years ago

Read 2 more answers

Which of the following statement is not a reason for sampling?

VladimirAG [237]

Answer:

Studying every single instance of a thing is impractical or too expensive

Step-by-step explanation:

With sampling we a have a lot of data without much effort.

3 0

2 years ago

Miss Smith save 5% on her recent Starbucks order because she is a Starbucks Rewards member if the cost of per purchase before th

Dima020 [189]

It would have been $5.48

4 0

2 years ago

Read 2 more answers

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

2 years ago