<img src="https://tex.z-dn.net/?f=%5Csqrt%7B12%7D%20%2B4%5Csqrt%7B25%7D%20-%5Csqrt%7B108%7D%20-%5Cfrac%7B1%7D%7B4%7D%20%5Csqrt%7

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3 years ago

B192%7D" id="TexFormula1" title="\sqrt{12} +4\sqrt{25} -\sqrt{108} -\frac{1}{4} \sqrt{192}" alt="\sqrt{12} +4\sqrt{25} -\sqrt{108} -\frac{1}{4} \sqrt{192}" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Eduardwww [97]3 years ago

7 0

20−6√3

Step by step Explanation:

√12+4√25−√108−1/4 √192

2√3+4×5-√108-2√3

2√3+20-√108-2√3

20−6√3

Alika [10]3 years ago

6 0

Answer:

5 is the answee

Step-by-step explanation:

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In XYZ, mX=90 and mY=30.In TUV,mU= 30 and mV=60. Which is true about the two triangles? XYZ=TUV, XYZ= VUT,No congruency statemen

Flauer [41]

Answer:

No congruency statement can be made because the side length are unknown.

Step-by-step explanation:

The sum of the measures of all interior angles in a triangle is always 180°.

In triangle XYZ,

$m\angle X=90^{\circ}\\ \\m\angle Y=30^{\circ},$

then

$m\angle X+m\angle Y+m\angle Z=180^{\circ}\Rightarrow m\angle Z=180^{\circ}-90^{\circ}-30^{\circ}=60^{\circ}$

In triangle TUV,

$m\angle U=30^{\circ}\\\\m\angle V=60^{\circ},$

then

$m\angle T+m\angle U+m\angle V=180^{\circ}\Rightarrow m\angle T=180^{\circ}-30^{\circ}-60^{\circ}=90^{\circ}$

We have two triangles with congruent angles but we have no information about side lengths. Therefore, can not be made because the side length are unknown. Correct option is last option.

6 0

3 years ago

Read 2 more answers

Cody was 165\,\text{cm}165cm tall on the first day of school this year, which was 10\%10% taller than he was on the first day of

Doss [256]

Answer:

165 cm.

Step-by-step explanation:

Let h be the height of Cody on the first day of school last year.

We have been given that Cody was 165 cm tall on the first day of school this year, which was 10% taller than he was on the first day of school last year.

To find the height of Cody on the first day of school last year, we need to find h such that h plus 10% of h equals 165. We can represent this information in an equation as:

$h+10\%\text{ of }h=165$