<img src="https://tex.z-dn.net/?f=%5Csqrt%7B12%7D%20%2B4%5Csqrt%7B25%7D%20-%5Csqrt%7B108%7D%20-%5Cfrac%7B1%7D%7B4%7D%20%5Csqrt%7

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2 years ago

B192%7D" id="TexFormula1" title="\sqrt{12} +4\sqrt{25} -\sqrt{108} -\frac{1}{4} \sqrt{192}" alt="\sqrt{12} +4\sqrt{25} -\sqrt{108} -\frac{1}{4} \sqrt{192}" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Eduardwww [97]2 years ago

7 0

20−6√3

Step by step Explanation:

√12+4√25−√108−1/4 √192

2√3+4×5-√108-2√3

2√3+20-√108-2√3

20−6√3

Alika [10]2 years ago

6 0

Answer:

5 is the answee

Step-by-step explanation:

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Question Help When purchasing bulk orders of batteries, a toy manufacturer uses this acceptance sampling plan: Randomly select

horrorfan [7]

Answer:

The probability is $P(X \le 2 ) = 0.9072$

The company will accept 90.72% of the shipment and will reject $(100 -90.72) = 9.2\%$ of the shipment , so many of the shipment are rejected

Step-by-step explanation:

From the question we are told that

The sample size is n = 36

The proportion that did not meet the requirement is $p = 0.03$

Generally the probability that the whole shipment is accepted is equivalent to the probability that there is at most 2 batteries that do not meet the requirement , this is mathematically represented as

$P(X \le 2 ) = [ P(X = 0 ) + P(X = 1 ) + P(X = 0)]$

=> $P(X \le 2 ) = [ [^{n}C_0 * (p)^{0} *(1-p)^{n-0} ] + [^{n}C_1 * (p)^{1} *(1-p)^{n-1} ] + [^{n}C_2 * (p)^{2} *(1-p)^{n-2} ]]$

Here C stands for Combination (so we will be making the combination function in our calculators )

=> $P(X \le 2 ) = [ [^{36}C_0 * (0.03)^{0} *(1-0.03)^{36-0} ] + [^{36}C_1 * (0.03)^{1} *(1-0.03)^{36-1} ] + [^{36}C_2 * (0.03)^{2} *(1-0.03)^{36-2} ]]$