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nata0808 [166]
3 years ago
9

7. Identify the correct congruence statement. ​

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
3 0

Step-by-step explanation:

in ∆ABC and ∆ADC

AB = AD (given)

AC = AC (common)

angle ACB = angle ACD = 90° (Given)

therefore,

∆ABC = ∆ADC

therefore, option C is correct

hope this helps you!

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Find the GCF of 18 and 36.<br> Group of answer choices<br><br> 63<br><br> 18<br><br> 36
Karo-lina-s [1.5K]

Answer:

18

Step-by-step explanation:

The GCF (Greatest Common Factor) for 18 and 36 would be 18 because, the GCF of two non-zero integers, x(18) and y(36), is the greatest positive integer m(18) that divides both x(18) and y(36) without any remainder.

5 0
3 years ago
Factor
vitfil [10]

Answer:

(x + 2) (x + 1) thus b: is the Answer

Step-by-step explanation:

Factor the following:

x^2 + 3 x + 2

The factors of 2 that sum to 3 are 2 and 1. So, x^2 + 3 x + 2 = (x + 2) (x + 1):

Answer: (x + 2) (x + 1)

8 0
3 years ago
John is 2 years younger than 3 times his sisters age, how old is his sister? Defineyour varieble and solve your equation.
Ann [662]
You need his sisters age to solve the problem. if y is the sisters age and x is Johns age, then the equation is
3y-2=x
4 0
3 years ago
Assume that all​ grade-point averages are to be standardized on a scale between 0 and 4. How many​ grade-point averages must be
guapka [62]

Answer:

a) The required sample size  n= 55011,57025

b) The sample size is not practical, because that size is extremely large and   would be very costly to collect, normally the size have to be significant but no to large to avoid cost unnecessary

Step-by-step explanation:

Range

σ = \frac{4-0}{4} = 1

E = 0,011 \\c= 99 %\\⇒ 0,99

Sample size can be determinate using equation:

n=(\frac{Z_{\alpha /2 * σ} }{E})^{2}

Using confidence level desired 99% Z_{\alpha /2} = 2,58

Table used :

<em>Confidence         Z_{\alpha/2 }</em>

<em>         90 %                    1,60</em>

<em>         95 %                    1,96</em>

<em>        </em><em> 99 %                    2,58</em>

<em>        99,9 %                  3,291</em>

So replacing:

n=(\frac{2,58 * 1 }{0,011})^{2}

n= 234,5454545^{2} \\n=55011,57025

6 0
4 years ago
Read 2 more answers
Round 3.44570830811 to the nearest hundred-thousandth.
Tcecarenko [31]

Answer:

3.44571

Step-by-step explanation:

The hundred thousands place is the fifth number after the decimal.

7 0
3 years ago
Read 2 more answers
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