The use of vaginal inserts of Lactobacillus to restore a healthy acidic environment is an example of probiotics.
<h3>What are probiotics?</h3>
Probiotic consumption is the intentional consumption of microorganisms that are considered "good" for the body and relatively safe to ingest. This is often done in an attempt to restore a healthy balance of microflora in distinct parts of the body, such as the one mentioned in this question.
Therefore, we can confirm that because this includes the intentional incorporation of bacteria with the end goal of restoring a healthy environment in the body, it can be considered an example of probiotics.
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Lipids is the organic compound that is generally not soluble in water and makes up an important part of biological membranes.
material culture includes all of the physical objects that people create and give meaning to. Cars, clothing, schools, computers, and books would be examples. An object only becomes part of culture after meaning have been given to it. A rock in a field has no meaning until it is used as a tool or to build a fence.
They help during times of disaster. Examples: Hurricanes, Tornadoes, and Earthquakes.
Answer:
a) 99.93%
b) 99.98%
Explanation:
Given that:
Total population size was only around 18 individuals ( for black-footed ferret)
If the annual survival rate in the wild was 0.4%.
a)
What is the probability that all 18 would have died in a single year?
To find that; we multiply the annual survival rate in the wild with the total population; which is:
(0.4%×18) = 0.072%
Then; we subtract it from a total of 100% in order to determine the probability that all 18 would have died in a single year.
= (100.00% - 0.072%)
= 99.93%
b)
What is the probability that all 18 would have died in a single year if canine distemper was present?
Given that;
Because of the presence of canine distemper disease, the annual mortality rate might have been as high as 0.89.
To determine the probability; we have:
1 - Annual mortality rate = annual survival rate
1 - 0.89 = 0.11 %
Therefore, 0.11% of 18 individuals = (0.0011 × 18)
= 0.0198%
Probability that all 18 would have died in a single year if canine distemper was present = 100 - probability of annual survival rate
= (100 - 0.0198)%
= 99.98%