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2 years ago

10

Please help and explain how you did it! Because I 4got....

2 answers:

Fynjy0 [20]2 years ago

5 0

Answer:

x = 6

Step-by-step explanation:

Step 1: Flip the equation.

x−7=−1

Step 2: Add 7 to both sides.

x−7+7=−1+7

x=6

Rom4ik [11]2 years ago

4 0

Answer:

x = 6

Step-by-step explanation:

you need to solve for x. so you have to get it alone

-1 = x - 7

add 7 to each side

6 = x

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Which is the sum of 3/10 and 1/3

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Step-by-step explanation:

$\: \: \: \: \: \frac{3}{10} + \frac{1}{3} \\ \\ = \frac{3 \times 3}{10 \times 3} + \frac{1 \times 10}{3 \times 10} \\ \\ = \frac{9}{30} + \frac{10}{30} \\ \\ = \frac{19}{30} \\ \\ so \: as \: you \: see \: here \: we \: should \: put \: same \: denominator \\ \: for \: both \: fractions. \: hope \: this \: helps.. \\ good \: luck$

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3 years ago

An angle measures 120°less than the measure if its supplementary angle. What is the measure of each angle

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Step-by-step explanation: 180 - 120 = 60.

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3 years ago

Estimate the answer to 65.78 + 13.43 by first rounding each number to the nearest tenth.

gizmo_the_mogwai [7]

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6 0

3 years ago

What is the antiderivative of 3x/((x-1)^2)

Maslowich

Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

Given

$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx$

$=3\cdot \int \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Apply\:u-substitution:}\:u=x-1$

$=3\cdot \int \frac{u+1}{u^2}du$

$\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}$

$=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)$

as

$\int \frac{1}{u}du=\ln \left|u\right|$ ∵ $\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)$

$\int \frac{1}{u^2}du=-\frac{1}{u}$ ∵ $\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

so

$=3\left(\ln \left|u\right|-\frac{1}{u}\right)$

$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Therefore,

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

4 0

3 years ago

Please help me on these questions.

KonstantinChe [14]

Answer:

1C

2A

3B

4D

Step-by-step explanation:

I did it

5 0

2 years ago