Its the third one im pretty sure
Answer: I can answer 20
I think....the answer... Is......2 1/2
1. Divide 135 by 8 which is equal to 16
2. Multiply 16 ×8 = 128
3. Subtract 135 - 128 =7
The seven represent the numerator so it would be 7/8.
The finally answer would be
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
Answer is <span>C. 4 × 10^5 D
</span><span>(2.8 × 10^9) ÷ (7 × 10^3)
= 0.4 * 10^6
=4 * 10^5</span>