9
27/9 = 3
54/9 = 6
81/9 = 9
Answer:
<u>Answer (a):</u>
s + l = 22 ... (i)
43s + 75l = 1234 ... (ii)
<u>Answer (b)</u>
9 large dogs.
Step-by-step explanation:
Paws at Play made a total of $1234 grooming 22 dogs.
Paws at Play charges $43 to groom each small dog and;
$75 for each large dog.
Let the number of small dogs be 's'
And the number of large dogs be 'l'
<u>A system of equations will be:</u>
s + l = 22 ... (i)
43s + 75l = 1234 ... (ii)
Solving this set of simultaneous equations by elimination, we simply multiply (i) by 43 to get;
43s + 43l = 946 ... (i)
43s + 75l = 1234 ... (ii)
Subtracting (i) from (ii) we get;
32l = 288 , l =
= 9
So there are 9 large dogs.
Answer:
X= 1 + 7/12
x = 1 - 7/12
Step-by-step explanation:
46: 24a+40
First we are going to take a look at a) 8(3a+5)
a) We then simplify it by multiplying the numbers inside the parenthesis by 8.
a) 24a+40
Now we ask ourselves, is this equivalent to 24a+40? YES!
So your answer for #46 is a) 8(3a+5)
I believe its B
i hope this helps :)