Answer:
I hope this helps you and you have an amazing day the answer
Width=12
Length=30
Step-by-step explanation:
L=2W+6
is
P=2L+2W
84=2(2W+6)+2W
84=4W+12+2W
84=6W+12
6W=84-12
6W=72
W=72/6
W=12 ans. for the width.
L=2*12+6=24+6=30 ans. for the length.
Proof:
84=2*30+2*12
84=60+24
84=84
<span>5x= 6x^2 -3
</span><span>6x^2 -5x -3
a = 6
b = -5
c = -3
x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +- </span><span>sq root (25 -(4*6*-3)] / 12
</span><span>x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +- </span><span>9.84886] / 12
x1 = </span><span><span><span>1.237405
</span>
</span>
</span>
<span>
x2 = </span><span><span><span>-0.404072
</span>
</span>
</span>
Answer:
A.
by the SAS postulate.
Step-by-step explanation:
We have been two triangles. We are asked to determine the theorem by which both triangles could be proven congruent.
We can see that side DF of triangle DEF is equal to side AC of triangle ABC.
We can also see that side BC of triangle ABC is equal to side EF of triangle DEF.
The including angle between sides AC and BC of triangle ABC is equal to the including angle between sides DF and EF of triangle DEF.
Since both triangles have two sides and their included angles equal, therefore, triangle ABC is congruent to triangle DEF by SAS (Side-Angle-Side) congruence and option A is the correct choice.
6
To solve this problem, you need to divide the total number of students going on the field trips with the number of students in each group.
44/7
= 6 R 2
Since, I assume there can <em>only</em> be groups of 7, the answer is 6.