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gtnhenbr [62]
3 years ago
6

Josh has a rewards card for a movie theater. He receives 15 points for becoming a rewards card holder. He earns 3.5 points for e

ach visit to the movie theater. He needs at least 55 points to earn a free movie ticket. Which inequality can Josh use to determine x, the minimum number of visits he need s to earn his first free movie ticket? *
a. 55 ≥ 3.5x + 15
b. 55 ≥ 15x + 3.5
c. 55 ≤ 3.5x + 15
d. 55 ≤ 15x + 3.5
Mathematics
1 answer:
Savatey [412]3 years ago
6 0

Answer:

C. 55 \leq 3.5x + 15

Step-by-step explanation:

i found it on google

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(-4,1) and (-8,7) <br><br> write an equation in slope-intercept form
Alchen [17]

Answer:

y = -2x - 9

Step-by-step explanation:

so we have our two points, (-4,-1) and (-8,7) What we need to do to find our slope is y2 - y1 over x2 - x1. Once plugging in the numbers and subtracting it should give you 8/-4. 8 divided by -4 is -2. m = -2. Now to find our "b" we plug in our slope, and plug in one of the two points into the format of y = mx + b.

-1 = -2(-4) + b

multiply -2 and -4

-1 = 8 + b

we subtract 8 from itself and -1

-9 = b

Our equation is y = -2x - 9

5 0
3 years ago
Please help due tomorrow don’t know how to do it
a_sh-v [17]

Slope is 1/3 for both triangles

6 0
2 years ago
What is the answer to rounding 12.3
AnnZ [28]
To round it would be 0-4 you keep the same # 5-up so in this case it would be 12 ,
5 0
2 years ago
PLEASE HELP
laila [671]
<h3><u>Option A</u></h3>

4 x^{2}+32 x-80=0 is the required equation to calculate width of rectangular frame that has a total area of 140 square inches.

<h3><u>Solution:</u></h3>

Given that,

Length of a rectangular frame is given as 2x + 10

Width of the rectangular frame is given as 2x + 6

Total area = 140 square inches

<em><u>The area of rectangular frame is given as:</u></em>

\text {area of rectangle}=\text {length } \times \text {width}

Plugging in values, we get

\begin{array}{l}{(2 x+10)(2 x+6)=140} \\\\ {4 x^{2}+12 x+20 x=80} \\\\ {4 x^{2}+32 x-80=0}\end{array}

This is the required equation to calculate width of rectangular frame

Solve the above quadratic equation to get the value of "x"

4 x^{2}+32 x-80=0

<em><u>Use the quadratic equation formula:</u></em>

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here a = 4 ; b = 32 ; c = -80

x=\frac{-32 \pm \sqrt{32^{2}-4(4)(-80)}}{2(4)}

x=\frac{-32 \pm \sqrt{2304}}{8}

x = 2 or x = -10

Now measurement cannot be negative, so taking the positve value of "x", we can calculate the width

So put "x" = 2

Width of the rectangular frame = 2x + 6 = 2(2) + 6 = 10

Thus the width of frame is 10 inches

4 0
3 years ago
M∠ABD=87°<br> m∠ABC=9x−1°<br> m∠CBD=6x+58 <br><br> Encuentra m∠ABC
Softa [21]

Answer: 9x - 1 = 9(2) - 1 = 17

Step-by-step explanation:

m∠ABD = m∠ABC + m∠CBD

87 = 9x -1 + 6x + 58

87 = 15x + 57

30 = 15x

2 = x

5 0
2 years ago
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