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kotegsom [21]
3 years ago
13

Use the elimination method to solve the ststem of equations.choose the correct ordered pair 10x+2y=22 3x-4y=-21

Mathematics
2 answers:
miv72 [106K]3 years ago
7 0
Answer: the ordered pair is (1, 6)

Explanation:

Ordered pair (1, 6)

denis-greek [22]3 years ago
7 0

Answer:

x=1 and y=6

Step-by-step explanation:

10x+2y=22

3x-4y=-21

First at all, you have to multiply both sides of this equation of 10x+2y=22, like this,

2(10x+2y)=2*22

*Put the 2 for the both sides.

Then, expand them.

20x+4y=44

When we have 20x+4y=44, we can eliminate with another equation.

20x+4y=44

3x-4y=-21

So, the first equation has +4y and the second equation has -4y, so we can use elimination method to eliminate one variable.

This time we can sum these equation to get one variable to get the answer easily. Like this...

20x+4y=44

3x-4y=-21

to become...

23x=23

x=23/23

x=1

When we get the equation like this, we can divide 23 by 23, so we can get the value of x. So, the value of x is 1.

When we know x is equal to 1, we can do the last part substitute x=1 into the second equation which is 3x-4y=-21.

The following steps is like this:

Substitute x=1 into 3x-4y=-21,

3(1)-4y= -21

3-4y= -21

Move the 3 to the another side, like this;

-4y= -21-3

-4y= -24

y= -24/ -4

y=6

*Be careful! When you calculate -24/-4 , you have to know how to eliminate the negative sign. (-) / (-) = +

Negative number divided by negative number is equal to positive number.

So, here we go! the value of x is 1 and the value of y is 6.

That is my solution and explanation from me. I hope you can understand. Bye!

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omeli [17]

This question is incomplete, the complete question is;

X and Y are independent Gaussian (Normal) random Variables. X has mean 13.9 and variance 5.2; Y has mean 6.9 and variance 3.8. . (a) Calculate P( W> 10)

Answer:

P( W> 10) is 0.1587

Step-by-step explanation:

Given that;

X ⇒ N( 13.9, 5.2 )

Y ⇒ N( 6.9, 3.8 )

W = X - Y

Therefore

E(W) = E(X) - E(Y)

= 13.9 - 6.9 = 7

Var(W) = Var(X) + Var(Y) -2COV(X.Y)

[ COV(X,Y) = 0 because they are independent]

Var(W) = 5.2 + 3.8 + 0

= 9

Therefore

W ⇒ N( 7, 9 )

so

P( W > 10 )

= 1 - P( W ≤ 10 )

= 1 - P( W-7 /3   ≤   10-7 /3 )

= 1 - P( Z ≤ 1 )           [ Z = W-7 / 3 ⇒ N(0, 1)  ]

from Standard normal distribution table, P( Z ≤ 1 )  = 0.8413

so

1 - P( Z ≤ 1 )  = 1 - 0.8413 = 0.1587

Therefore P( W> 10) is 0.1587

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Let 5x = amt for Brian

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