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Nuetrik [128]
2 years ago
8

Find an equation for the nth term of the arithmetic sequence.

Mathematics
1 answer:
amm18122 years ago
4 0

Answer:

a_n=-301 +37(n-1)

Step-by-step explanation:

arithmetic sequence formula:  a_n=a +(n-1)d

where a is the first term and d is the common difference

Given:

  a_{10}=32

⇒ a +(10-1)d=32

⇒ a+9d=32

Given:

    a_{12}=106

⇒ a +(12-1)d=106

⇒ a+11d=106

Rearrange the first equation to make a the subject:

a = 32 - 9d

Now substitute into the second equation and solve for d

    (32 - 9d) + 11d = 106

⇒ 32 + 2d = 106

⇒ 2d = 106 - 32 = 74

⇒ d = 74 ÷ 2 = 37

Substitute found value of d into the first equation and solve for a:

a + (9 x 37) = 32

a + 333 = 32

a = 32 - 333 = -301

Therefore, the equation is: a_n=-301 +37(n-1)

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Given:

Set A: 1 4 4 4 5 5 5 8

Mean: 4.5

Standard dev: 1.9

 

Set B:

Mean: 4.5

Standard dev: 2.45

 

% =  90 

Set A:

Standard Error, SE = s/ √n =    1.9/√8 = 0.67  

Degrees of freedom = n - 1 =   8 -1 =  7   

t- score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.67 = 1.272685913

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.272685913 = 3.23

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.272685913 = 5.77

The 90% confidence interval is [3.23, 5.77]

 

Set B:

Standard Error, SE = s/ √n =    2.45/√8 = 0.87  

Degrees of freedom = n - 1 =   8 -1 = 7   

t- Score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.87 = 1.641094994

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.641094994 = 2.86

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.641094994 = 6.14

The 90% confidence interval is [2.86, 6.14]

 

<span>We can obviously see that sample B has more variation in the scores than sample A. The fact that the standard deviation is 2.45 for B and 1.9 for A). Therefore, they yield dissimilar confidence intervals even though they have the same mean and range.</span>

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2 years ago
Read 2 more answers
Costs 21.36 +1.17x=73
Ierofanga [76]

Answer:

what are we actually solving for?....

anyways I had a suggestion ion know if it's right or wrong....

<em>Isolate</em><em> </em><em>the</em><em> </em><em>variable</em><em> </em><em>by</em><em> </em><em>diving</em><em> </em><em>each</em><em> </em><em>side</em><em> </em><em>by</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>don't</em><em> </em><em>contain</em><em> </em><em>the</em><em> </em><em>vari</em><em>able</em><em>.</em>

<em>Therefore</em><em> </em><em>x</em><em>=</em><em>7</em><em>.</em><em>2</em>

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3 years ago
Need help asap
Marizza181 [45]
Its b for sure i worked it out
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40% of the students in a school are boys. lf there are 240 boys, how many student are therein the school?
Stells [14]
40/100 = 96/240

Hope this helps
3 0
2 years ago
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