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2 years ago

What is the basic purpose of the osi physical layer?.

Computers and Technology

1 answer:

andrew11 [14]2 years ago

3 0

The basic purpose of the osi physical layer: To coordinates rules for transmitting bits.

<h3>Osi physical layer</h3>

OSI Physical layer is important as it help to coordinates the rules for transmitting bits and it is responsible for transmitting bits from one device to another or from one computer to another.

In order for the transmission to successful take place in OSI Physical layer the bits must be encoded into signals in which the bits are then transmitted across a communication channel.

Inconclusion the basic purpose of the osi physical layer: To coordinates rules for transmitting bits.

Learn more about Osi physical layer here:brainly.com/question/24793290

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The equation of certain traveling waves is y(x.t) = 0.0450 sin(25.12x - 37.68t-0.523) where x and y are in

NNADVOKAT [17]

Answer:

A. 0.0450

B. 4

C. 0.25

D. 37.68

E. 6Hz

F. -0.523

G. 1.5m/s

H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

I. -1.67m/s.

Explanation:

Given the equation:

y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)

Standard wave equation:

y(x, t)=Asin(kx−ωt+ϕ)

a.) Amplitude = 0.0450

b.) Wave number = 1/ λ

λ=2π/k

From the equation k = 25.12

Wavelength(λ ) = 2π/25.12 = 0.25

Wave number (1/0.25) = 4

c.) Wavelength(λ ) = 2π/25.12 = 0.25

d.) Angular frequency(ω)

ωt = 37.68t

ω = 37.68

E.) Frequency (f)

ω = 2πf

f = ω/2π

f = 37.68/6.28

f = 6Hz

f.) Phase angle(ϕ) = -0.523

g.) Wave propagation speed :

ω/k=37.68/25.12=1.5m/s

h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.

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