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konstantin123 [22]
3 years ago
7

Complete the table to investigate dilations of exponential functions. A 4-column table has 5 rows. The first column is labeled x

with entries negative 2, negative 1, 0, 1, 2. The second column is labeled 2 Superscript x with entries one-fourth, one-half, a, d, 4. The third column is labeled 3 times 2 Superscript x with entries three-fourths, three-halves, b, e, 12. The fourth column is labeled 2 Superscript 3 x with entries StartFraction 1 Over 64 EndFraction, one-eighth, c, f, 64. a = b = c = d = e = f =
Mathematics
1 answer:
morpeh [17]3 years ago
7 0

Answer:

a= 1

b= 3

c=1

d= 2

e=6

f=8

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The graph of the invertible function f is shown on the grid below <br> What is the value of f^-1(6)
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Step-by-step explanation:

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A new car is purchased for 15500 dollars. The value of the car depreciates at 6.5% per year. What will the value of the car be,
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Answer:

$10356,22

Step-by-step explanation:

15500*(1-(6,5/100))^6=10356,22

3 0
3 years ago
Write the ratios for sin A and cos A. Need help.
klio [65]

Answer:

Your answer would be C, Sin A= 3/5 cos A= 4/5

Step-by-step explanation:

Remember Soh-cah-toa

Soh stands for sin= opposite/hypotenuse

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In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6965 subjects randomly sele
vladimir1956 [14]

The hypothesis test shows that we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%

<h3>What is the claim that the return rate is less than 20% by using a statistical hypothesis method?</h3>

The claim that the return rate is less than 20% is p < 0.2. From the given information, we can compute our null hypothesis and alternative hypothesis as:

\mathbf{H_o :p =0.2}

\mathbf{H_i:p < 0.2}

Given that:
Sample size (n) = 6965

Sample proportion \mathbf{\hat p = \dfrac{x}{n} = \dfrac{1302}{6965} \sim0.1869}

The test statistics for this data can be computed as:

\mathbf{z = \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}}}

\mathbf{z = \dfrac{0.1869 -0.2}{\sqrt{\dfrac{0.2(1-0.2)}{6965}}}}

\mathbf{z = \dfrac{-0.0131}{0.0047929}}

z = -2.73

From the hypothesis testing, since the p < alternative hypothesis, then our test is a left-tailed test(one-tailed.

Hence, the p-value for the test statistics can be computed as:

P-value = P(Z ≤ z)

P-value = P(Z ≤ - 2.73)

By using the Excel function =NORMDIST (-2.73)

P-value = 0.00317

P-value ≅ 0.003

Therefore, we can conclude that since P-value is less than the significance level at ∝ = 0.01, we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%

Learn more about hypothesis testing here:

brainly.com/question/15980493

#SPJ1

3 0
2 years ago
The enrollment at Ousley Jr. High School dropped by 60 students over a 5-year period. What is the average yearly drop in enrollm
Snezhnost [94]

Answer:

The average yearly drop in enrollment is 12.

Step-by-step explanation:

The average refers to the central value in a group of numbers and with the information provided, you can find the average by dividing the number of students that dropped out of the school by the number of years over which that ocurred:

number of students= 60

number of years= 5

60/5=12

According to this, the answer is that the average yearly drop in enrollment is 12.

3 0
3 years ago
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