Area of rectangular board = length (inches) x width (inches) = 12" x 16" = 192 in²
Area of the border is given as 128 in²
Adding the area of the board and the border gives (192 + 128)in² = 320 in²
Set this up as the algebraic equation (x + 12)(x + 16) = 320 and solve for x:
Remember to use the FOIL method, which is multiplying the terms in the order of first, outer, inner, last.
x² + 12x + 16x + 192 = 320
x² + 28x + 192 - 320 = 0
x² + 28x - 128 = 0
solve for the two x values:
(x + 32)(x - 4) = 0, and knowing we only need the positive x value
x = 4 or 4 inches is the width of the border
Don't you mean 66 divided by eight?
That would equal 8.25, or 8 remainder 2.
if you did mean 8 divided by 66, your answer is not one of your choices.
The answer you're looking for is A
Answer:
4
Explanation:
I’ve attached my work
Hope it helps, Let me know if you have anymore questions/concerns !
Have a nice rest of your day :)
