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3 years ago

How many sixteenths are in 15/16

Mathematics

2 answers:

11111nata11111 [884]3 years ago

6 0

Fifteen sixteenths 15 16ths

LekaFEV [45]3 years ago

3 0

There are 15 sixteenths in 15/16

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A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

2 years ago

What is the value of x3 × y1 when x = 5 and y = 10

katovenus [111]

Answer:

150

Step-by-step explanation:

To solve the problem, put 5 instead of x, so 5*3

and put 10 instead of y, so 10*1

when combined,

(5*3) * (10*1)

= 15 * 10

= 150

Hope this helps!!

Let me know if I'm wrong...

8 0

2 years ago

Solve for x.<br> 3(x+3) = -18 . A. x= -9<br> B.x= -7<br> c. x=-5<br> D. X=-3

slavikrds [6]

It is A x= -9 I just did the assignment so yes, this means it is -9 I hope m answer helps you out.

3 0

2 years ago

Solve for m. 2= m/2 - 7 whats the answer?

xz_007 [3.2K]

Linear equations are all solved the same way. Figure out the operations performed on the variable. Undo those in reverse order.

Here, the variable is
- divided by 2
- has -7 added.

In reverse order, we undo these operations by
- adding 7
- multiplying by 2.

Whatever we do to one side of an equation, we must also do to the other side. That is how the equal sign remains valid.

2 = m/2 -7
2 +7 = m/2 -7 +7 . . . . . add 7
9 = m/2 . . . . . . . . . . . . simplify
2*9 = 2*m/2 . . . . . . . . multiply by 2
18 = m . . . . . . . . . . . . . simplify. (You know that 2/2 = 1, and m*1 = m.)

The answer is m = 18.

_____
Check:
.. 2 = 18/2 -7
.. 2 = 9 -7 . . . . . . . true. The answer checks OK.

7 0

2 years ago

A number is chosen at random from 1 to 50 find the probability of selecting composite numbers

Anit [1.1K]

34/50= .68 or 68%

hope it helps

3 0

2 years ago