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3 years ago

The frequency of vibrations of a vibrating violin string isgiven by

Mathematics

1 answer:

arlik [135]3 years ago

7 0

Answer:a. [tex] $f\propto L$ [\tex]

b. [tex] f \propto \sqrt{T} [\tex]

c. [tex] f \propto \frac{1}{\sqrt{P}} [\tex]

I. Decrease in length increases leads to increase in pitch.

II. Increase in tension leads to increase in pitch.

III. Increase in linear density reduces the pitch

Step-by-step explanation: I. Since the frequency is inversely proportional to the length increase in length leads to decrease in frequency likewise decrease in length leads to increase in frequency.

II. Since the frequency is directly proportional to the square root of the tension increase in tension leads to increase in frequency likewise decrease in tension leads to decrease in frequency.

III.since the frequency is inversely proportional to the square root of the linear density so increase in linear density leads to decrease in frequency and likewise decrease in linear density leads to increase in frequency.

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What is the value of -4x + 12 if x = -4

Nezavi [6.7K]

Answer:

Step-by-step explanation:

substitute x for negative four -4(-4)+12=

solve -4 * -4= 16

add 16 and 12 equals 28

5 0

3 years ago

Read 2 more answers

Mrs. johnson's and mr. wei's classes are participating in the Meridian School arts and crafts exhibit. Their spaces will be next

Nat2105 [25]

Answer:

See explanation

Step-by-step explanation:

Ms. Johnson space has 48 carpet squares.

Mr. Wei space has 36 carpet squares.

Factorize these two numbers:

$48=2\cdot 2\cdot 2\cdot 2\cdot 3\\ \\36=2\cdot 2\cdot 3\cdot 3$

All common factors are 1, 2, 3, 4, 6, 12

<u>All possibilities:</u>

1. If Ms. Johnson space width and Mr. Wei space width is 1 carpet, then Ms. Johnson space length is 48 carpets and Mr. Wei space length is 36 carpets.

2. If Ms. Johnson space width and Mr. Wei space width is 2 carpets, then Ms. Johnson space length is 24 carpets and Mr. Wei space length is 18 carpets.

3. If Ms. Johnson space width and Mr. Wei space width is 3 carpets, then Ms. Johnson space length is 16 carpets and Mr. Wei space length is 12 carpets.

4. If Ms. Johnson space width and Mr. Wei space width is 4 carpets, then Ms. Johnson space length is 12 carpets and Mr. Wei space length is 9 carpets.

5. If Ms. Johnson space width and Mr. Wei space width is 6 carpets, then Ms. Johnson space length is 8 carpets and Mr. Wei space length is 6 carpets.

6. If Ms. Johnson space width and Mr. Wei space width is 12 carpets, then Ms. Johnson space length is 4 carpets and Mr. Wei space length is 3 carpets.

4 0

3 years ago

Read 2 more answers

Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x

Svet_ta [14]

Answer:

$A^{'}$ = {1,3,5,7,9,....}

$B^{'}$ = {1,2,4,5,7,8,10,11,13,14......}

$C^{'}$ = {1,2,3,4,5}

$D^{'}$ = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

$A^{'}$ = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

$A^{'}$ = {1,3,5,7,9,....}

$B^{'}$ = U-B = {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

$B^{'}$ = {1,2,4,5,7,8,10,11,13,14......}

$C^{'}$ = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

$C^{'}$ = {1,2,3,4,5}

$D^{'}$ = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

$D^{'}$ = {10,11,12,13,14,15,......}

8 0

2 years ago

A radio station installs a vhf radio tower that stands 1500 ft

aleksley [76]

Whats the question u just told us some of the information

4 0

3 years ago

An important assumption underlying inferences from a linear regression is that variance in the response variable is reasonably c

rewona [7]

Answer:

A. True

Step-by-step explanation:

Linear regression is "an analysis that assesses whether one or more predictor variables explain the dependent (criterion) variable. The regression has five key assumptions:

1) Linear relationship : We need to check if the dependnet variable present a linear relationshipThe linearity assumption can best be tested with scatter plots in order to check if we have outliers in the data.

2) Multivariate normality : "The linear regression analysis requires all variables to be multivariate normal". And we can check this with a histogram or a Q-Q-Plot, usually Normality can be checked with a goodness of fit test like the Kolmogorov-Smirnov test or Shapiro Wilks test.

3) No or little multicollinearity : "Multicollinearity occurs when the independent variables are too highly correlated with each other". And we can check this with a correlation matrix, variance inflation factor (VIF's), correlation index and other statistics.

4) No auto-correlation : The "Autocorrelation happens when the residuals are not independent from each other in the data". And usually we can test this with the Durbin-Watson test.

5) Homoscedasticity: MEans that we need constant variance for the linear model. The scatter plot is good way to check whether the data are homoscedastic. And we can interpret this condition as "that variance in the response variable is reasonably consistent across the range of an explanatory factor (otherwise known as homoscedasticity)"

So then the statement is TRUE.

5 0

3 years ago