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2 years ago

What is 5% of 20? Pls help!!

Mathematics

2 answers:

Sergio [31]2 years ago

5 0

Answer:

Step-by-step explanation:

5% = 5/100 = 0.05

So 5% of 20 = 0.05 x 20 = 1

VMariaS [17]2 years ago

3 0

Answer:

Step-by-step explanation:

to find the percentage of a number, multiply the % by the number.

5% converted to a decimal is 0.05. (5/100)

So 20 times 0.05 is 1

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Factorise: x³ + 32x + 20.

LenKa [72]

Answer:

cant be factored

Step-by-step explanation:

7 0

2 years ago

Ursula tosses two six-sided number cubes and MULTIPLIES the numbers rolled. Which of these is a list of the outcomes of the two

Black_prince [1.1K]

Answer:

3,4,5,6,7,8

Step-by-step explanation:

sum of 2 with other possible numbers:

2+1, 2+2, 2+3, 2+4, 2+5, 2+6

3, 4, 5, 6, 7, 8

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3 years ago

2. Fran needs a bookcase to hold all of his math books. He decides to try to build the bookcasepictured below. He needs to buy t

astraxan [27]

Let's rewrite the mixed number as a fractions:

$\begin{gathered} 3\frac{2}{3}=\frac{11}{3} \\ 4\frac{1}{2}=\frac{9}{2} \end{gathered}$

Therefore, the total length will be:

$3\cdot(\frac{11}{3})+2(\frac{9}{2})+4=24ft$

5 0

7 months ago

Suppose that f(x)=3x+1....

skad [1K]

Answer:

Step-by-step explanation:

f(x) = 3x+1

f(x+h) = 3(x+h)+1 = 3x+3h+1

f(x+h) - f(x)= 3x+3h+1-3x-1 = 3h

3h/h=3

4 0

2 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago