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viva [34]
2 years ago
15

What is the slop on this graph ?

Mathematics
2 answers:
Helen [10]2 years ago
7 0

Answer:

3/4

Step-by-step explanation:

Up 3, left 4

Schach [20]2 years ago
6 0

Ok, a slope is M = rise/run = y2-y1/x2-x1

Therefore, we would divide y/x

So, your answer would be 4/2, which is 2.

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Nadusha1986 [10]
Is that all to the problem ?
8 0
3 years ago
Read 2 more answers
A washer and a dryer cost $858 combined. The washer costs $92 less than the dryer. What is the cost of the dryer?
Soloha48 [4]

Answer:

383

Step-by-step explanation:

Let dryer be d.

(d + 92) + d = 858

2d + 92 = 858

      -92 =  -92

---------------------

    2d = 766

    ----    ------

     2        2

       d = 383

The dryer is $383

Hope this helped.

3 0
3 years ago
Read 2 more answers
WORTH A LOT OF POINTS. WILL GIVE BRAINLEIST THINGY TO WHOEVER SOLVES IT!​
alukav5142 [94]

Answer:

the area of the small square 4c

the total area of the 4 triangles is 2ab

a^2+2ab+b^2 = a^2+2ab+b^2

subtracting gives 2ab from both sides gives us a^2+b^2

Step-by-step explanation:

6 0
3 years ago
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What is the simplified form of 10,000x^64
rusak2 [61]
Answer: 100x<span>³²

Hope it helps
Brainliest? </span>
6 0
3 years ago
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Factor each.<br><br><br> Please help!
Naddika [18.5K]

Answer:

1) The factors of  x^2-3x+2=0 are \mathbf{(x-1)(x-2)=0}

Option C is correct.

3) The factors of  x^2+2x-8=0 are \mathbf{(x-2)(x+4)=0}

Option B is correct.

Step-by-step explanation:

1) Factor : x^2-3x+2=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0

So, factors of  x^2-3x+2=0 are \mathbf{(x-1)(x-2)=0}

Option C is correct.

3) Factor: x^2+2x-8=0

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0

So, factors of  x^2+2x-8=0 are \mathbf{(x-2)(x+4)=0}

Option B is correct.

7 0
3 years ago
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