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Elanso [62]
3 years ago
12

What is the square root of 79

Mathematics
2 answers:
andreev551 [17]3 years ago
6 0
79 is a prime, so we cannot reduce it. \sqrt{79} =8.888194417315589
stepan [7]3 years ago
3 0
The square root of a # would be the two same #'s that are multiplied to equal a number
so you would do √79, which is a ongoing number, and equals about 8.888...
just do √79 in a calculator

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<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4

Evaluate the combination factors.

So, we have:

(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4

Evaluate the exponents and the products

(2x -3)^4 = 16x^4  + 96x^3  +216x^2 -216x + 81

Hence, the value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

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Using the equation of the test statistic, it is found that with an increased sample size, the test statistic would decrease and the p-value would increase.

<h3>How to find the p-value of a test?</h3>

It depends on the test statistic z, as follows.

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You can learn more about p-values at brainly.com/question/26454209

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