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andreyandreev [35.5K]
2 years ago
12

Which of the following about GH and GJ is true?

Mathematics
2 answers:
Pani-rosa [81]2 years ago
5 0

Answer:

B

Step-by-step explanation:

vfiekz [6]2 years ago
5 0
B because you can see that GJ is three boxes long and GH is only two boxes long
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Turn the sentence into an expression <br><br> 5.three times the sum of two consecutive<br> integers
ryzh [129]

3(x+x+1)

hope this helps

8 0
3 years ago
Evaluate 5 + 6 · 2 – 8 ÷ 4 + 7 using the correct order of operations
Natali5045456 [20]
Do solve this you use PEMDAS. This stands for:
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Because there are no parentheses or exponents in this equation, we go straight to the division.

1) 8 divided by 4 equals two so we rewrite the equation. 5+6 x 2 - 2 + 7.

2) Next in order of pemdas is multiplication. Yes I know that in pemdas multiplication does come before division but it doesn’t matter in this problem which you do first. So now we do 6 x2 =12. We then rewrite the equation 5+12-2+7.

3) lastly, addition and subtraction are grouped together and you can just do it in order of the problem. So we do 5+12=17. 17-2=15. And 15+7=22.

So the final answer is: 22
8 0
3 years ago
Read 2 more answers
Plz help me i dont understand
stiks02 [169]

Answer:

23

hope it helped you!!

BTW, angle 1 + angle 2 = 180

7 0
3 years ago
Read 2 more answers
Are the ratios 20:9 and 2:1 equivalent?<br> yes or no
marusya05 [52]

Answer:

No

Step-by-step explanation:

Do they have common factors?

No which is why they are not able to be simplified further

so no

5 0
2 years ago
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James is running late to his cousin's wedding and drives the 45 miles between his house and the wedding location 20 miles per ho
netineya [11]

Answer:

(r + 20)t = r

Step-by-step explanation:

Distance is constant in the scenario above, distance from home to wedding and wedding back home is the same.

From wedding back home. :

Recall : Distance = speed * time

Distance = r * 1 hour

From home to wedding :

Speed = 20 mph more ; r + 20

Time = t

Distance = (r + 20)* t = (r +20)t

Since the distance are the same, we can equate both :

(r + 20)t = r * 1

= (r + 20)t = r

5 0
3 years ago
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